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alina1380 [7]
3 years ago
12

Balance the following skeleton reaction and identify the oxidizing and reducing agents: Fill in all blanks with numbers so if th

e term is not in the equation make it 0. CrO42- (aq) + N2O(g)+ H+(aq) + OH-(aq) + H2O(l) LaTeX: \longrightarrow⟶ Cr3+(aq) + NO(g) + H+(aq) + OH-(aq) + H2O(l) oxidizing agent is (enter just the formula of the species, e.g. CrO42-,N2O, Cr3+,NO, H2O, H+, OH-) reducing agent is (enter just the formula of the species, e.g. CrO42-,N2O, Cr3+,NO, H2O, H+, OH-)
Chemistry
1 answer:
Mila [183]3 years ago
4 0

Answer:

2(CrO_4)^{2-} (aq) + 3N_2O(g)+ 10H^+(aq) + \longrightarrow 2Cr^{3+}(aq) + 6NO(g)  + 5H_2O(l)

Reducing agent: nitrogen.

Oxidizing agent: chromium.

Explanation:

Hello,

In this case, the first step is to rewrite the undergoing chemical reaction indicating the oxidation state for each atom as shown below:

(Cr^{+6}O^{-2}_4)^{2-} (aq) + N^+_2O^{-2}(g)+ H^+(aq) + OH^-(aq) + H_2O(l) \longrightarrow Cr^{3+}(aq) + N^{+2}O^{-2}(g) + H^+(aq) + OH^-(aq) + H_2O(l)

In such a way, we observe the following half-reactions:

* Reduction as chromium undergoes a decrease in its oxidation state:

(Cr^{+6}O_4^{-2})^{2-}+8H^++3e^-\rightarrow Cr^{+3}+4H_2O

* Oxidation as nitrogen undergoes an increase in its oxidation state:

N^+_2O^{-2}+H_2O\rightarrow 2N^{+2}O^{-2}+2H^++2e^-

In such a way, we state that the nitrogen is the reducing agent as it is oxidized and chromium the oxidizing agent as it is reduced, therefore, the balanced chemical reaction turns out:

2(CrO_4)^{2-} (aq) + 3N_2O(g)+ 10H^+(aq) + \longrightarrow 2Cr^{3+}(aq) + 6NO(g)  + 5H_2O(l)

Best regards.

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Answer:

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Determine the approximate amount of potassium hydrogen phthalate, KHP, that you will need to neutralize 6.00 ml of 0.100 M NaOH.
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Answer:

potassium hydrogen phthalate KHP MOLAR MASS = 204.233 glmol

to get 1000 ml

Molar concentration = Mass concentration/Molar Mass

mass concentration = molar concentration x molar mass

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so to get 1L

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if 20.4233g is for 1000ml

then to 6.00 ml

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according to the equation below

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number of moles of NaOH is equal to that of KHP

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Answer:

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