The question is somewhat poorly posed because the equation doesn't involve <em>θ</em> at all. I assume the author meant to use <em>x</em>.
sec(<em>x</em>) = csc(<em>x</em>)
By definition of secant and cosecant,
1/cos(<em>x</em>) = 1/sin(<em>x</em>)
Multiply both sides by sin(<em>x</em>) :
sin(<em>x</em>)/cos(<em>x</em>) = sin(<em>x</em>)/sin(<em>x</em>)
As long as sin(<em>x</em>) ≠ 0, this reduces to
sin(<em>x</em>)/cos(<em>x</em>) = 1
By definition of tangent,
tan(<em>x</em>) = 1
Solve for <em>x</em> :
<em>x</em> = arctan(1) + <em>nπ</em>
<em>x</em> = <em>π</em>/4 + <em>nπ</em>
(where <em>n</em> is any integer)
In the interval 0 ≤ <em>x</em> ≤ 2<em>π</em>, you get 2 solutions when <em>n</em> = 0 and <em>n</em> = 1 of
<em>x</em> = <em>π</em>/4 <u>or</u> <em>x</em> = 5<em>π</em>/4
Plug the points into the equation.
Ex. y=3x-5
(X,y)
1. (5,10): 10=3(5)-5
15-5=10; point 1 is valid
-1=3(-2)-5
-1=-6-5
-1 does not equal -11
Point 2 is not valid
Same process for letter B
Answer:
A=1 B=3 C=1 D=2 E=6 F=8
Step-by-step explanation:
the second part is b= y=3 times2^x
The correct answer is:
D. ∠FGE≅∠NMP
Explanation:
The symmetric property states that if two quantities are equal (or congruent), you can "flip" them around the equals sign (or congruence sign).
This means since EFG is congruent to HJK, then HJK is congruent to EFG.