V=LW/H
VH=LW
H=LW/V
That’s the answer
Answer: Let's see why
Pure solid and liquid compounds possess sharp melting and boiling points. Therefore, melting and boiling points of a compound can be used as a criteria of purity. ... Sometimes during cooling minute quantity of the substance (solid which is being purified) is added to the solution to facilitate the initial crystallisation.
Explanation:
Answer:
P = 0.444 atm
Explanation:
The reaction of decomposition of H₂S is:
H₂S(g) ⇄ H₂(g) + S(g)
<em>Initial</em> 0.245 0 0
<em>Equilibrium </em>0.245-x x x
The equilibrium constant (Kp) of the above reaction is the following:
(1)
Knowing that initally, only H₂S is present at P = 0.245, the Kp of equation (1) at equilibrium is:
Using the quadratic formula we get x₁ = 0.199 and x₂ = -1.058.
Taking only the possitive number we have that:
Therefore, the total pressure in the container at equilibrium is:
I hope it helps you!
Answer:
Then pressure will double
Explanation:
PV = nRT
P = nRT / V
If all other variables are kept constant, P will be proportional to n i.e
P1 / n1 = P2 / n2
n = 1
P1 = P
n2 = 2
P2 =?
P1 / n1 = P2 / n2
P /1 = P2/2
Cross multiply
P2 = 2P
Therefore, if an additional 1mole of the gas is added, the pressure will double
The kinetic energy of an object increases when heat is added.