Number of electron pairs = \frac{1}{2}[V+N-C+A]
2
1
[V+N−C+A]
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
SbCl_5SbCl
5
:
In the given molecule, antimony is the central atom and there are five chlorine as monovalent atoms.
The number of electron pairs are 5 that means the hybridization will be sp^3dsp
3
B and geometry of the molecule will be trigonal bipyramidal.
<u>Answer:</u> The concentration of hydrogen gas at equilibrium is 
<u>Explanation:</u>
We are given:
Initial moles of hydrogen sulfide gas = 0.47 moles
Volume of the container = 3.0 L
The molarity of solution is calculated by using the equation:

So, 
The given chemical equation follows:

<u>Initial:</u> 0.1567
<u>At eqllm:</u> 0.1567-2x 2x x
The expression of
for above equation follows:
![K_c=\frac{[H_2]^2[S_2]}{[H_2S]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_2%5D%5E2%5BS_2%5D%7D%7B%5BH_2S%5D%5E2%7D)
We are given:

Putting values in above equation, we get:

So, equilibrium concentration of hydrogen gas = 
Hence, the concentration of hydrogen gas at equilibrium is 
Explanation:
The first wave was found to have a wavelength of 3 x 10⁵ m and the second wave had a wavelength of 3 x 10⁴ m
We need to find which wave have a higher frequency.
The relation between frequency and wavelength is given by :

Let f₁ and f₂ be the frequency of wave 1 and wave 2.

And

Hence, the wave having less wavelength will have higher frequency. The wave having wavelength 3 x 10⁴ m will have higher frequency.
The mass number of aluminium hydroxide is 78 thus, the number of moles in 0.745 g is:
no. of moles= mass/ RFM
= 0.745/78
=0.00955moles
Therefore the 0.00955 moles should be in the 35.18 ml
therefore 1000ml of the solution will have:
(0.00955ml×1000ml)/35.18
=0.2715moles
The solution will be 0.27M hydrochloric acid
I think it's 2 I tried looking it up because I was not sure.