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svet-max [94.6K]
4 years ago
7

A youth organization is having its annual pinewood model car race. The unpowered cars, like the one shown below, are lined up at

the top of a hill and ready to begin.
What gives the cars their potential energy?
A.
gravity
B.
their speed
C.
friction
D.
their wheels

Chemistry
1 answer:
a_sh-v [17]4 years ago
3 0

Gravity

Explanation:

The unpowered cars as shown gets their potential energy from their acceleration due to gravity and the height above the ground of the hill.

Potential energy is the energy due the position or a body. It is energy primarily at rest of a body.

 Potential energy = m x g x h

Where:

m = mass

g = acceleration due to gravity

h = height of the hill.

 

learn more:

Potential energy brainly.com/question/10770261

#learnwithBrainly

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Predict the shape of the molecule.
GuDViN [60]

Number of electron pairs = \frac{1}{2}[V+N-C+A]

2

1

[V+N−C+A]

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

SbCl_5SbCl

5

:

In the given molecule, antimony is the central atom and there are five chlorine as monovalent atoms.

The number of electron pairs are 5 that means the hybridization will be sp^3dsp

3

B and geometry of the molecule will be trigonal bipyramidal.

6 0
2 years ago
2 H2S(g) ⇄ 2 H2(g) + S2(g) Kc = 9.3× 10-8 at 400ºC 0.47 moles of H2S are placed in a 3.0 L container and the system is allowed t
Anon25 [30]

<u>Answer:</u> The concentration of hydrogen gas at equilibrium is 1.648\times 10^{-3}M

<u>Explanation:</u>

We are given:

Initial moles of hydrogen sulfide gas = 0.47 moles

Volume of the container = 3.0 L

The molarity of solution is calculated by using the equation:

\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of the solution}}

So, \text{Initial molarity of hydrogen sulfide gas}=\frac{0.47}{3}=0.1567M

The given chemical equation follows:

                          2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

<u>Initial:</u>                  0.1567

<u>At eqllm:</u>           0.1567-2x       2x         x

The expression of K_c for above equation follows:

K_c=\frac{[H_2]^2[S_2]}{[H_2S]^2}

We are given:

K_c=9.3\times 10^{-8}

Putting values in above equation, we get:

9.3\times 10^{-8}=\frac{(2x)^2\times x}{(0.1567-2x)^2}\\\\x=8.24\times 10^{-4}

So, equilibrium concentration of hydrogen gas = 2x=(2\times 8.24\times 10^{-4})=1.648\times 10^{-3}M

Hence, the concentration of hydrogen gas at equilibrium is 1.648\times 10^{-3}M

7 0
3 years ago
Two waves were analyzed with some high-tech instrumentation. The first wave was found to have a wavelength of 3 x 10 m and the s
a_sh-v [17]

Explanation:

The first wave was found to have a wavelength of 3 x 10⁵ m and the second wave had a wavelength of 3 x 10⁴ m

We need to find which wave have a higher frequency.

The relation between frequency and wavelength is given by :

c=f\lambda

Let f₁ and f₂ be the frequency of wave 1 and wave 2.

f_1=\dfrac{c}{\lambda_1}\\\\f_1=\dfrac{3\times 10^8}{3\times 10^5}\\\\=1000\ Hz

And

f_2=\dfrac{c}{\lambda_2}\\\\f_2=\dfrac{3\times 10^8}{3\times 10^4}\\\\=10000\ Hz

Hence, the wave having less wavelength will have higher frequency. The wave having wavelength 3 x 10⁴ m will have higher frequency.

8 0
3 years ago
What is the molar concentration of the acid if 35.18 mL of hydrochloric acid was required to neutralize 0.745 g of ALUMINUM hydr
Makovka662 [10]

The mass number of aluminium hydroxide is 78 thus, the number of moles in 0.745 g is:

no. of moles= mass/ RFM

= 0.745/78

=0.00955moles

Therefore the 0.00955 moles should be in the 35.18 ml

therefore 1000ml of the solution will have:

(0.00955ml×1000ml)/35.18

=0.2715moles

The  solution will be 0.27M hydrochloric acid  

3 0
3 years ago
How many atoms of hydrogen-1 are in a 1.007-g sample?
Greeley [361]
I think it's 2 I tried looking it up because I was not sure.
8 0
3 years ago
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