Answer:
22-6
Step-by-step explanation:
there isnt a variable so the answer is 16
Answer:
E(X) = 6
Var(X) = 3.394
Step-by-step explanation:
Let X represent the number of carp caught out of the 20 fishes caught. Now, if we are to assume that each
of the (100, 20) ways to catch the 20 fishes will be equally likely.
Thus, we can say that X fulfills a hypergeometric
distribution with parameters as follows;
n = 20, N = 100, k = 30
Formula for expected mean value in hypergeometric distribution is;
E(X) = nk/N
E(X) = (20 × 30)/100
E(X) = 6
Formula for variance is;
Var(X) = (nk/N) × [((n - 1)(k - 1)/(N-1))) + (1 - nk/N)]
Var(X) = ((20 × 30)/100) × [((20 - 1)(30 - 1)/(100 - 1)) + (1 - (20 × 30/100)]
Var(X) = 6 × 0.5657
Var(X) = 3.394
I think the best answer would be F.
When √10 is converted into a decimal it is 3.16, and F is the most close to that.
Hope this helps!
Answer:
p value = 0.302
Step-by-step explanation:
Given that all cars can be classified into one of four groups: the subcompact, the compact, the midsize, and the full-size. There are five cars in each group. Head injury data (in hic) for the dummies in the driver's seat are listed below.
H_0: All cars have same mean values
H_a: atleast two cars have different mean values
(Two tailed anova test)
Anova: Single Factor
SUMMARY
Groups Count Sum Average Variance
Subcompact 5 3444 688.8 48502.7
compact 5 2879 575.8 4582.7
Midsize 5 2534 506.8 18720.2
Full size 5 2689 537.8 23905.2
ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 94825 3 31608.33 1.321 0.302 3.24
Within Groups 382843.2 16 23927.7
Total 477668.2 19
Since p value of 0.302 is greater than 0.05 significance level we accept null hypothesis.
p value = 0.302
