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3 years ago

How many vertices does ten hexagon have. IT 15 POINTS

Mathematics

2 answers:

Korvikt [17]3 years ago

6 0

Step-by-step explanation:

one hexagon have 6vertices. ten hexagon have 60 vertices

never [62]3 years ago

3 0

Answer: 6 sides and 6 vertices

Step-by-step explanation:

A hexagon has 6 six sides and 6 vertices

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Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B

JulsSmile [24]

Answer:

They will do rounds together again in 11 minutes and 40 seconds.

Step-by-step explanation:

Security A rounds every 2 minutes and 20 seconds in the gate 1.

That is, after 2*60 + 20 = 120 + 20 = 140 seconds.

Security B rounds every 1 minute and 40 seconds in the gate 2.

That is, after 1*60 + 40 = 60 + 40 = 100 seconds.

After how many minutes they will rounds together again?

First, we find this is seconds, which is the least common multiple between 140 and 100. Factoring them by prime factors:

140 - 100|2

70 - 50|2

35 - 25|5

7 - 5|5

7 - 1|7

1 - 1

lcm(140,100) = 2*2*5*5*7 = 700 seconds

They will do rounds together again in 700 seconds, which is 11 minutes and 40 seconds.

5 0

2 years ago

The IQ test is designed such that the scores on it are normally distributed with a mean of 100 and a standard deviation of 15. I

kozerog [31]

Answer:

130

Step-by-step explanation:

A standard deviation is 15, so 2 standard deviation is 30, 2 standard deviations above 100 is 100+30=130

5 0

2 years ago

Convert each rational number into its decimal form. 1. 1/3 2. 1/6 3. 1/9

stepladder [879]

Answer:

1. 0.33 2. 0.16 3. o.11

Step-by-step explanation:

5 0

2 years ago

A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a

sdas [7]

Answer:

$y=-\dfrac{13}{49}x^2$

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

$y=ax^2+bx+c$

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

$-13=a(-7)^2+b(-7)+c$

$49a-7b+c=-13$

(x,y) = (7,-13)

$-13=a(7)^2+b(7)+c$

$49a+7b+c=-13$

(x,y) = (0,0)

$0=a(0)^2+b(7)+c$

$c=0$

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

$49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13$

$49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13$

we can solve these two equation using the elimination method, by simply adding the two equations

$\quad\quad49a-7b=-13\\+\quad49a+7b=-13$

------------------------------

$\quad\quad 98a=-26$

$\quad\quad a=-\dfrac{13}{49}$

Now we can plug this value of a in any of the two equations.

$49a-7b=-13$

$49\left(-\dfrac{13}{49}\right)-7b=-13$

$-13-7b=-13$

$-7b=0$

$b=0$

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

$y=\left(-\dfrac{13}{49}\right)x^2+0x+0$

$y=-\dfrac{13}{49}x^2$

$49y=-13x^2$

This our equation of the arch!

5 0

3 years ago

Find the midpoint of the segment with given endpoints k(1.7,-7.9) and l(8.5,-8.2)

zhenek [66]

I think it would be 5.2

6 0

3 years ago