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3 years ago

7

Reflect the following across y=-x

1 answer:

omeli [17]3 years ago

7 0

Answer:

1=-1

5=-6

1=-5

Step-by-step explanation:

hope that helped...

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What is pie?<br> need it for math hw

professor190 [17]

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3 years ago

HELP ASAP!! 10 points!

masha68 [24]

$\dfrac{5}{7}\ of\ 100:\\\\\dfrac{5}{7}\cdot100=\dfrac{5\cdot100}{7}=\dfrac{500}{7}=\dfrac{70+28+2}{7}=\dfrac{70}{7}+\dfrac{28}{7}+\dfrac{2}{7}\\\\=10+4+\dfrac{2}{7}=14\dfrac{2}{7}\\\\\dfrac{2}{7}\ \text{is smaller than}\ \dfrac{1}{2}.\ \text{Therefore}\ 14\dfrac{2}{7}\approx14\\\\Answer:\ \boxed{14}$

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3 years ago

Please can you tell me what 1+100448 is for 73 points. (just to give points to who ever wants them

LenaWriter [7]

Answer:

that would be 100449 ! LOL

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Can somebody help me do this?

saveliy_v [14]

Answer:

a) Point Q

b) Sides SQ,RQ

c)Angle RQT and Angle Q

Step-by-step explanation:

6 0

3 years ago

What is the quotient of (x3 - 3x2 + 5x – 3) = (x - 1)?

IRINA_888 [86]

Note: Consider "÷" sign instead of "=".

Given:

$(x^3-3x^2+5x-3)\div (x-1)$

To find:

The quotient.

Solution:

We have,

$(x^3-3x^2+5x-3)\div (x-1)$

It can be written as

$=\dfrac{x^3-3x^2+5x-3}{x-1}$

Splitting the middle terms, we get

$=\dfrac{x^3-x^2-2x^2+2x+3x-3}{x-1}$

$=\dfrac{x^2(x-1)-2x(x-1)+3(x-1)}{x-1}$

Taking out the common factor (x-1), we get

$=\dfrac{(x-1)(x^2-2x+3)}{x-1}$

Cancel the common factors.

$=x^2-2x+3$

The quotient is $x^2-2x+3$ .

Therefore, the correct option is D.

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2 years ago

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