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lianna [129]
3 years ago
9

Relations and Functions: 1) Select True or False for each statement. True or False, A straight line on a coordinate plane always

represents a function. True or False, The equation y=2x+1 represents a function.
Mathematics
1 answer:
matrenka [14]3 years ago
5 0
I believe the answer is going to be False. if im wrong I apologize
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Find the value of a²+b <br> if...<br> a=-2 and b=5
Nana76 [90]

Answer:

9

Step-by-step explanation:

a²+b

Substituting values,

=> (-2)^2+5

=> 4 + 5

=> 9

4 0
3 years ago
Read 2 more answers
Is (2, 2) a solution of y &lt; 4x – 6?
Roman55 [17]

Answer:

No

Step-by-step explanation:

To see if (2,2) is a solution, substitute them into the inequality and see if it is true.

2 is our x value, and 2 is also our y value

y < 4x – 6

2< 4(2)– 6

2 < 8 – 6

2 < 2

This statement is false. 2 is not less than 2, so (2,2) is not a solution to this equation.

6 0
2 years ago
10) Which point in the table is not on the same
horsena [70]
The answer to the question above is D. (5.7, 31.3)
8 0
2 years ago
Suppose that 15% of the fields in a given agricultural area are infested with the sweet potato whitefly. One hundred fields in t
hram777 [196]

Answer:

a.\mu=15

b.\mu=7.8586 \ and  \ \mu=22.1414

c. Choice A- Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.

Step-by-step explanation:

a.Binomial distribution is defined by the expression

P(X=k)=C_k^n.p^k.(1-p)^{n-k}

Let n be the number of trials,n=100

and p be the probability of success,p=15\%

The mean of a binomial distribution is the probability x sample size.

\mu=np=100\times0.15=15

b.Limits within which p is approximately 95%

sd of a binomial distribution is given as:\sigma=\sqrt npq\\q=1-p

Therefore, \sigma=\sqrt(100\times0.015\times0.85)=3.5707

Use the empirical rule to find the limits. From the rule, approximately 95% of the observations are within to standard deviations from mean.

sd_1=>\mu-2\sigma=15-2\times3.3507=7.8586\\sd_2=>\mu-2\sigma=15+2\times3.3507=22.1414

Hence, approximately 95% of the observations are within 7.8586 and 22.1414 (areas of infestation).

c.  x=45 is not within the limits in b above (7.8586,22.1414). X=45 appears to be a large area of infestation. A.Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.

4 0
3 years ago
A group of 72 students went on a field trip the students traveled in vans with an equal number of boys and girls and each Van a
timurjin [86]
30 girls and 42 boys so idk this makes no sense and I'm older than you
5 0
3 years ago
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