All categories

3 years ago

Multiple choice can someone please answer please

Mathematics

1 answer:

Furkat [3]3 years ago

5 0

Answer:

n = 6

Step-by-step explanation:

Since the triangles are similar then the ratio of corresponding sides are equal, that is

$\frac{GH}{QR}$ = $\frac{FH}{PR}$ , substitute values

$\frac{n}{9}$ = $\frac{4}{6}$ ( cross- multiply )

6n = 36 ( divide both sides by 6 )

n = 6

You might be interested in

Problem Page

qwelly [4]

Answer:

355

Step-by-step explanation:

I think..........

4 0

3 years ago

Y = -4x + 3<br> 8x + 2y = 8<br> Solve by using elimination.

ValentinkaMS [17]

Answer:

The equations are not compatible

Step-by-step explanation:

y = -4x + 3

8x + 2y = 8

substitute for y:

8x + 2(-4x + 3) = 8

simplify:

8x - 8x + 6 = 8

6 ≠ 8

3 0

3 years ago

What is the answer for these problems?

givi [52]

A. 16^{5}

C. 4^{5}

i don't know b. tho

5 0

4 years ago

B a C Which of these angles are adjacent angles?

BigorU [14]

Answer: a and c

Step-by-step explanation:

I know it’s not b but isn’t adjacent angel two angels?

Correct me if I’m wrong

3 0

3 years ago

A = √7 + √c and b = √63 + √d where c and d are positive integers.

mrs_skeptik [129]

Answer:

$\displaystyle a:b=\frac{1}{3}$

Step-by-step explanation:

<u>Ratios </u>

We are given the following relations:

$a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]$

$b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]$

$\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]$

From [3]:

$9c=d$

Replacing into [2]:

$b=\sqrt{63}+\sqrt{9c}$

We can express 63=9*7:

$b=\sqrt{9*7}+\sqrt{9c}$

Taking the square root of 9:

$b=3\sqrt{7}+3\sqrt{c}$

Factoring:

$b=3(\sqrt{7}+\sqrt{c})$

Find the ration a:b:

$\displaystyle a:b=\frac{\sqrt{7}+\sqrt{c}}{3(\sqrt{7}+\sqrt{c})}$

Simplifying:

$\boxed{a:b=\frac{1}{3}}$

3 0

3 years ago