First, distribute the 2 on the right side of the equation so you get 4a-26. Then add 26 to both sides so you have 7a+21 =4a. Subtract 7a and get 21 = -3a. Divide by -3 and your final answer is -7.
3x +4 >17
3x > 13
13/3
x is at least 4
Answer:
x 2-2 3-3
y 5 5 7 7
Step-by-step explanation:
Each domain, or x value, can only be matched with one y value, so given this, the third one is the answer since every domain is only matched with one range, or in other words, there are no repeating domains in on the x row of the table.
Note: The missing diagram is attached below for a reference.
Answer:
Step-by-step explanation:
Given:
- ∠T and ∠V are right angles.
-
║ 
To Prove:
- Δ
≅ Δ
As
∠ 
≅ ∠ 
≅ 
(Given)
Side 
≅
║ 
and is a transverse
So,
∠ 
≅ ∠ 
![\left[alternate\:\:interior\:\:angles\right]](https://tex.z-dn.net/?f=%5Cleft%5Balternate%5C%3A%5C%3Ainterior%5C%3A%5C%3Aangles%5Cright%5D)
Thus,
- Δ ≅ Δ
Keywords: proof, paragraph, logic, reason
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For the first question the answer is 1/13. then for the second it is 1/2 and for the third it is 3/10.
case.
