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3 years ago

What is the composition of carbohydrates

1 answer:

8 0

Answer - A carbohydrate is a naturally occurring compound, or a derivative of such a compound, with the general chemical formula Cx(H2O)y, made up of molecules of carbon (C), hydrogen (H), and oxygen (O). Carbohydrates are the most widespread organic substances and play a vital role in all life. hopes this helps

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The pH of an acidic solution is 2.47. what is the [H+]

solmaris [256]

$pH=-\log[H^{+}]\\\\\implies [H^{+}] =10^{-pH}=10^{-2.47}=0.0034~M$

8 0

3 years ago

Relative humidity is described as: Group of answer choices a basically unused concept when it comes to weather topics. the amoun

Bad White [126]

Correct answer:

The relative humidity is best described as the amount of water vapor in the air at a given temperature expressed as a percentage of the water vapor capacity of the air.

What is relative humidity?

The ratio of the current absolute humidity to the highest absolute humidity is known as relative humidity (which depends on the current air temperature).

Water vapor is also measured by relative humidity, which is stated as a percentage but RELATIVE to the air's temperature. In other words, it is a comparison between the amount of water vapor that is actually present in the air and the maximum amount of vapor that is possible for the air at the current temperature.

With the same quantity of absolute/specific humidity, air will have a HIGHER relative humidity if it is cooler and a LOWER relative humidity if it is warmer because warm air may contain more water vapor (moisture) than cold air. The actual amount of moisture (absolute humidity) in the air is what we "feel" outside.

Learn more about relative humidity here,

brainly.com/question/14104185

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5 0

2 years ago

Iron (III) oxide and hydrogen react to form iron and water, like this: Fe 03(s)+3H9)2Fe(s)+3HO) At a certain temperature, a chem

belka [17]

The question is incomplete, here is the complete question:

Iron (III) oxide and hydrogen react to form iron and water, like this:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, Iron, and water at equilibrium has the following composition.

Compound Amount

Fe₂O₃ 3.95 g

H₂ 4.77 g

Fe 4.38 g

H₂O 2.00 g

Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

Answer: The value of equilibrium constant for given equation is $1.0\times 10^{-4}$

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

For hydrogen gas:

Given mass of hydrogen gas = 4.77 g

Molar mass of hydrogen gas = 2 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

$\text{Molarity of hydrogen gas}=\frac{4.77}{2\times 8.9}\\\\\text{Molarity of hydrogen gas}=0.268M$

For water:

Given mass of water = 2.00 g

Molar mass of water = 18 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

$\text{Molarity of water}=\frac{2.00}{18\times 8.9}\\\\\text{Molarity of water}=0.0125M$

For the given chemical equation:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

The expression of equilibrium constant for above equation follows:

$K_{eq}=\frac{[H_2O]^3}{[H_2]^3}$

Concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

$K_{c}=\frac{(0.0125)^3}{(0.268)^3}\\\\K_{c}=1.0\times 10^{-4}$

Hence, the value of equilibrium constant for given equation is $1.0\times 10^{-4}$

6 0

4 years ago

You are given a bottle of NaOH of an unknown concentration. You are tasked with determining the concentration of this solution.

Salsk061 [2.6K]

Answer:

0.07975 M NaOH

Explanation:

First determine the molarity of your acid, KHP. Convert grams to moles using the MW given and then divide by the volume of water.

0.3175 g KHP • (1 mol KHP / 204.2 g KHP) = 0.001555 mol KHP

0.001555 mol KHP / 0.040 L = 0.03888 M KHP

The reaction between KHP and NaOH is one-to-one, so you can just use M1V1 = M2V2 to solve for M2 (the molarity of NaOH).

M1 = 0.03888 M KHP

V1 = 40 mL

M2 = ? M NaOH

V2 = 19.45 mL NaOH

(0.03888 M KHP)(40 mL) = M2(19.5 mL NaOH)

M2 = 0.07975 M NaOH

4 0

3 years ago

Calculate the molarity of the final solution of Erythrocin B (MW 879.9 g/mol) if a .5028g sample is dissolved in water diluted t

Mashcka [7]

Answer:

2.857 × 10⁻⁴ M

Explanation:

First, we will calculate the molarity of the solution 1.

M = mass of solute / molar mass of solute × liters of solution

M = 0.5028 g / 879.9 g/mol × 0.100 L

M = 5.714 × 10⁻³ M

We can find the concentration of the final solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 5.714 × 10⁻³ M × 5 mL / 100 mL

C₂ = 2.857 × 10⁻⁴ M

7 0

4 years ago

What is the composition of carbohydrates￼

What is the composition of carbohydrates