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sveta [45]
3 years ago
13

Which of the following sets are equal to {x | x > 9 and x < 2}

Mathematics
1 answer:
Arada [10]3 years ago
7 0

Answer:

  { }

Step-by-step explanation:

There are no numbers that are both greater than 9 and less than 2. The expression describes the empty set.

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The coordinates of A, B,and C in the diagram are A(p,4), B(6,1), C(9,q). What equation correctly relates p and q?
murzikaleks [220]
I don't see any diagram. So, I'll just wing it.

Value of q:
p, 6, 9 ⇒ there is a difference of 3. The sequence increases by 3. So, it can be assumed that the p is equal to 3. A(p,4) ⇒ A(3,4)

Value of q:
4, 1, q ⇒ there is a difference of 3. The sequence decreases by 3. So, it can be assumed that q is equal to -2. C(9,-2)
 
        p        q
A     3        4     ⇒ 3 + 4 = 7
B     6        1     ⇒ 6 + 1 = 7
C     9       -2    ⇒ 9 + (-2) = 7

Notice that the sequence has an equation of p + q = 7.


7 0
3 years ago
Read 2 more answers
Solve for the compound inequality 6b &lt; 42 or 4b + 12 &gt; 8.
Anuta_ua [19.1K]

Answer:

-1<b<7, or i suppose b.

Step-by-step explanation:

6b<42

b<7

4b+12>8

4b>-4

b>-1

6 0
3 years ago
What is 65% of 20?<br><br><br><br><br><br> ye
irga5000 [103]

Answer:

13

Step-by-step explanation:

x/20 = 65%/100

20 x 65 = 1300

1300 divided by 100 = 13

5 0
2 years ago
Read 2 more answers
Factor this equation<br> 4x^2+12x-7
Levart [38]
4x^2+12x-7=0\\\\a=4;\ b=12;\ c=-7\\\Delta=b^2-4ac\\\\\Delta=12^2-4\cdot4\cdot(-7)=144+112=256 \ \textgreater \  0\\\\therefore\\x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{256}=16\\\\x_1=\dfrac{-12-16}{2\cdot4}=\dfrac{-28}{8}=\boxed{-\dfrac{7}{2}}\\\\x_2=\dfrac{-12+16}{2\cdot4}=\dfrac{4}{8}=\boxed{\dfrac{1}{2}}
3 0
3 years ago
16 - x = -2 solve for x
poizon [28]

Answer:

16 - x = -2

16 + 2 = x

x = 18

hope it helps!

4 0
2 years ago
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