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Nataly [62]
3 years ago
8

PLEASE ANSWER ASAP!!! Which graph is a histogram?

Mathematics
2 answers:
mixer [17]3 years ago
4 0
The answer is B
Sorry if it’s wrong
musickatia [10]3 years ago
3 0
Spring sports, a historigram is specifically numerically based.
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Im so so sad worse day pls
Korvikt [17]

Formula: base x height

Therefore: 4x3 = 12

Hope this helps!

7 0
2 years ago
Read 2 more answers
-4|6b-8|≤ 12<br><br> what is the answer?
densk [106]
This is probably the answer I’m not 100% sure

8 0
3 years ago
The slope formula can be used to prove that a triangle has:
lisabon 2012 [21]

Answer:

a right angle

Step-by-step explanation:

The best and most correct answer among the choices provided by the question is the second choice "a right angle"The formula for finding the slope of a line on a coordinate plane is (y2 - y1) / (x2 - x1), where (x2, y2) and (x1, y1) represent two distinct points on the line. This is also known as "change in y over change in x" or "rise over run."I hope my answer has come to your help. God bless and have a nice day ahead!




8 0
2 years ago
The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg
julia-pushkina [17]

Answer:

Approximately 101\; \rm ft (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

  • Let \rm O denote the observer.
  • Let \rm A denote the top of the tree.
  • Let \rm R denote the base of the tree.
  • Let \rm B denote the point where line \rm AR (a vertical line) and the horizontal line going through \rm O meets. \angle \rm B\hat{A}R = 90^\circ.

Angles:

  • Angle of elevation of the base of the tree as it appears to the observer: \angle \rm B\hat{O}R = 51^\circ.
  • Angle of elevation of the top of the tree as it appears to the observer: \angle \rm B\hat{O}A = 57^\circ.

Let the length of segment \rm BR (vertical distance between the base of the tree and the base of the hill) be x\; \rm ft.

The question is asking for the length of segment \rm AB. Notice that the length of this segment is \mathrm{AB} = (x + 20)\; \rm ft.

The length of segment \rm OB could be represented in two ways:

  • In right triangle \rm \triangle OBR as the side adjacent to \angle \rm B\hat{O}R = 51^\circ.
  • In right triangle \rm \triangle OBA as the side adjacent to \angle \rm B\hat{O}A = 57^\circ.

For example, in right triangle \rm \triangle OBR, the length of the side opposite to \angle \rm B\hat{O}R = 51^\circ is segment \rm BR. The length of that segment is x\; \rm ft.

\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}.

Rearrange to find an expression for the length of \rm OB (in \rm ft) in terms of x:

\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}.

Similarly, in right triangle \rm \triangle OBA:

\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}.

Equate the right-hand side of these two equations:

0.810\, x \approx 0.649\, (x + 20).

Solve for x:

x \approx 81\; \rm ft.

Hence, the height of the top of this tree relative to the base of the hill would be (x + 20)\; {\rm ft}\approx 101\; \rm ft.

6 0
3 years ago
What is the SLOPE of a line PERPENDICULAR to the Given equation<br> y = 1/3x + 1
elixir [45]

Answer:

slope for perpendicular line is -3

Step-by-step explanation:

just flip the reciprocal for the slope and change the positive/negative sign

5 0
3 years ago
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