Perimeter of a rectangle = 2L + 2W
Perimeter = 39
W = 8.5
we plug those into the perimeter equation and get
2L + 2(8.5) = 39
simplify
2L + 17 = 39
subtract 17 from both sides
2L = 22
divide both sides by 2
L = 11
therefore the length of the sheet of paper is 11 in.
It might be mmmm idk I’m too dome
C=2pir
20pi=2pir
20pi/2pi=2pir/2pi
R=10
Height=10/2=5
Two circles surface areas is
2*pir^2
2pi10^2
2*100pi
200pi
The cylindrical part is
2pirh
2pi*10*5
100pi
Add 100pi+200pi=300pi
