Answer:
The length of the segment F'G' is 7.
Step-by-step explanation:
From Linear Algebra we define reflection across the y-axis as follows:
, 
(Eq. 1)
In addition, we get this translation formula from the statement of the problem:
, 
(Eq. 2)
Where:
- Original point, dimensionless.
- Transformed point, dimensionless.
If we know that 
and 
, then we proceed to make all needed operations:
Translation
Reflection
Lastly, we calculate the length of the segment F'G' by Pythagorean Theorem:
![F'G' = \sqrt{(5-5)^{2}+[(-1)-6]^{2}}](https://tex.z-dn.net/?f=F%27G%27%20%3D%20%5Csqrt%7B%285-5%29%5E%7B2%7D%2B%5B%28-1%29-6%5D%5E%7B2%7D%7D)
The length of the segment F'G' is 7.
I think its 6 but im not sure to be exactly right
<span>If the condition means conventional/regular rectangular piece of paper, then it is, probably,
rectangle of 8+3+3 = 14 inches wide and 3+10+3+10 = 26 inches long.</span>
Answer:
a = 120 cm²
Step-by-step explanation:
n = number of sides
edge length
40/n
divide the polygon into n congruent triangles
a = (1/2)(edge * apothem) * number of triangles
a = (1/2)(40/n)(6) * n
n cancels out
a = (1/2)(40)(6)
a = 120 cm²
