<h2>The initial velocity is 2.3
![\sqrt{gR}](https://tex.z-dn.net/?f=%5Csqrt%7BgR%7D)
</h2>
Explanation:
Suppose the speed of car at point A is u .
Its kinetic energy K =
mu²
At point B , its kinetic energy =
K
and its gravitational potential energy =
K = m g h = 2 m g R
here height h = 2 R ( radius of circle )
From the principle of conservation of energy
m u² =
m u² + 2 m g R
m u² = 2 m g R
Therefore u =
= 2.3 ![\sqrt{gR}](https://tex.z-dn.net/?f=%5Csqrt%7BgR%7D)
Answer:
u breathe lol nice ok bro
Answer:
The distance on the screen between the first-order bright fringes for each wavelength is 3.17 mm.
Explanation:
Given that,
Wavelength of red = 660 nm
Wavelength of blue = 470 nm
Separated d= 0.30 mm
Distance between screen and slits D= 5.0 m
We need to calculate the distance for red wavelength
Using formula for distance
![y=\dfrac{\lambda D}{d}](https://tex.z-dn.net/?f=y%3D%5Cdfrac%7B%5Clambda%20D%7D%7Bd%7D)
Where, D = distance between screen and slits
d = separation of slits
Put the value into the formula
![y=\dfrac{660\times10^{-9}\times5.0}{0.30\times10^{-3}}](https://tex.z-dn.net/?f=y%3D%5Cdfrac%7B660%5Ctimes10%5E%7B-9%7D%5Ctimes5.0%7D%7B0.30%5Ctimes10%5E%7B-3%7D%7D)
![y=11\ mm](https://tex.z-dn.net/?f=y%3D11%5C%20mm)
For blue wavelength,
Put the value into the formula again
![y'=\dfrac{470\times10^{-9}\times5.0}{0.30\times10^{-3}}](https://tex.z-dn.net/?f=y%27%3D%5Cdfrac%7B470%5Ctimes10%5E%7B-9%7D%5Ctimes5.0%7D%7B0.30%5Ctimes10%5E%7B-3%7D%7D)
![y'=7.83\ mm](https://tex.z-dn.net/?f=y%27%3D7.83%5C%20mm)
We need to calculate the distance on the screen between the first-order bright fringes for each wavelength
Using formula for distance
![\Delta y=y-y'](https://tex.z-dn.net/?f=%5CDelta%20y%3Dy-y%27)
![\Delta y=11-7.83](https://tex.z-dn.net/?f=%5CDelta%20y%3D11-7.83)
![\Delta y=3.17\ mm](https://tex.z-dn.net/?f=%5CDelta%20y%3D3.17%5C%20mm)
Hence, The distance on the screen between the first-order bright fringes for each wavelength is 3.17 mm.
<span>The question is asking us what is BEST to say about a runner who is running at a constant velocity? A constant velocity (=speed) means that they are not getting faster or slower - they are running exactly as fast all the time. This meanst that their speed does not change, so their change of speed is equal to 0. A change of speed is called acceleration so their C. Their acceleration is zero. - C is the correct answer. </span>
If force is applied at 30 degree with the horizontal
then first we will find the components of force in two directions
![F_x = 20 cos20](https://tex.z-dn.net/?f=F_x%20%3D%2020%20cos20)
![F_y = 20 sin30](https://tex.z-dn.net/?f=F_y%20%3D%2020%20sin30)
now we can find normal force by balancing the forces in Y direction
![F_n + Fy = mg](https://tex.z-dn.net/?f=F_n%20%2B%20Fy%20%3D%20mg)
![F_n + 20 sin30 = 3*10](https://tex.z-dn.net/?f=F_n%20%2B%2020%20sin30%20%3D%203%2A10)
![F_n + 10 = 30](https://tex.z-dn.net/?f=F_n%20%2B%2010%20%3D%2030)
![F_n = 20 N](https://tex.z-dn.net/?f=F_n%20%3D%2020%20N)
now since block is moving with constant speed
so here forces along horizontal plane will be balanced also
![F_x = F_f](https://tex.z-dn.net/?f=F_x%20%3D%20F_f)
![F_f = 20 cos30](https://tex.z-dn.net/?f=F_f%20%3D%2020%20cos30)
![F_f = 17.3 N](https://tex.z-dn.net/?f=F_f%20%3D%2017.3%20N)
Now the weight of the box is defined as
![W = mg](https://tex.z-dn.net/?f=W%20%3D%20mg)
now plug in all values
![W = 3*10 = 30 N](https://tex.z-dn.net/?f=W%20%3D%203%2A10%20%3D%2030%20N)