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Stels [109]
3 years ago
10

Scientists refer to half of the planets as inner planets because they are relatively close to the Sun. They refer to the other h

alf as outer planets. Using the data in the table, classify the planets into one of the two groups.
Physics
1 answer:
Korvikt [17]3 years ago
5 0

You've made it very very very very difficult for us to "... use the data in the table ...", by simply not letting us see the table.

However, we're used to that kind of thing here at Brainly.  You see, we have done so much with so little for so long that NOW, we can do nearly anything with almost nothing in virtually no time.  

Hence and therefore, despite your best efforts to render this question impenetrable due to acute lack of data, I was able to walk a short distance down the hall, and consult with today's Astronomy expert.  When I showed him the question, he chortled, and quoth:  "ANYbody could answer this one if they HAVE the data in the table, but if you're really Brainly, you know jour stoff, and jou don need no stinkin table."

-- The "inner planets" are Mercury, Venus, Earth, and Mars.

-- The "outer planets" are Jupiter, Saturn, Uranus, and Neptune.

-- Pluto used to be an 'outer' planet too, but now it's not even a planet.  How the mighty have fallen !

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The output voltage of a power supply is normally distributed with mean 5 V and standard deviation 0.02 V. If the lower and upper
-BARSIC- [3]

To solve this problem we will apply the normal distribution, with which we will obtain the probability that the given event will occur. Concepts such as the mean and standard deviation will be present throughout the solution of the problem. Increasing or decreasing the average would change the location or center point of the curve. The change in the standard deviation would lead to the change in the dispersion of the data. As the standard deviation increases, the curve would become flatter.

Let X be the output voltage of power supply

X∼N (5,0.02^2)

A

The lower and upper specifications for voltage are 4.95 V and 5.05 V, respectively

P(4.95

P(4.95

P(4.95

P(4.95

P(4.95

Hence probability that a power supply selected at random will conform to the specifications on voltage is 0.9876

8 0
3 years ago
An umbrella tends to move upward on a windy day because _____.
masha68 [24]
E. all of the above

An umbrella tends to move upward on a windy day because _<span>A. buoyancy increases with increasing wind speed </span>
<span>B. air gets trapped under the umbrella and pushes it up </span>
<span>C. the wind pushes it up </span>
<span>D. a low-pressure area is created on top of the umbrella </span>

3 0
3 years ago
. Find the weight (weight = mg) of a 17 kg crate of books.
White raven [17]

Answer:

It is 37.4786

5 0
3 years ago
2) A motorcycle is moving at a constant speed of 40 km/h. How long does it take the motorcycle to
docker41 [41]

Answer:

2 hours

Explanation:

The motorcycle travels 40 km per hour.

80km / 40km/h = 2 hours.

7 0
4 years ago
Read 2 more answers
You plan to take a trip to the moon. Since you do not have a traditional spaceship with rockets, you will need to leave the eart
hichkok12 [17]

Answer:

v = 3.5 \times 10^5 m/s

Explanation:

At some distance from the Earth the force of attraction due to moon is balanced by the force due to Moon

so we will have

\frac{GM_em}{r^2} = \frac{GM_m}{(d-r)^2}

now we have

\frac{d - r}{r} = \sqrt{\frac{M_m}{M_e}}

\frac{3.844\times 10^8 - r}{r} = \sqrt{\frac{7.36 \times 10^{22}}{5.9742\times 10^{24}}}

so we will have

r = 3.46 \times 10^8 m

Now by energy conservation

-\frac{GM_e}{R_e} - \frac{GM_m}{d - (R_e + R_m)} + \frac{1}{2}v^2 = -\frac{GM_e}{r} - \frac{GM_m}{d - r}

-6.26 \times 10^{8} - 13046 + \frac{1}{2}v^2 = -1.15 \times 10^6 - 1.28 \times 10^5

v = 3.5 \times 10^5 m/s

7 0
3 years ago
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