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Serggg [28]
2 years ago
6

When you travel in an elevator (which moves linearly in space), the ___________ detect when the elevator is accelerating or dece

lerating.
Physics
1 answer:
Shtirlitz [24]2 years ago
4 0

We can confirm that when you travel in an elevator, the utricle and saccule detect when the elevator is moving.

<h3>What are the utricle and saccule?</h3>

These are small organs located in the inner ear. They serve a very important function in our everyday life. These otolith organs are responsible for the detection of movement and provide us with a sense of spatial orientation. They accomplish this by stimulating very small, hair-like cells with a specialized fluid.

Therefore, we can confirm that when you travel in an elevator, the utricle and saccule detect when the elevator is accelerating or decelerating.

To learn more about the inner ear visit:

brainly.com/question/3535321?referrer=searchResults

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When we add or remove energy from a substance, what kind of changes can we observe? Can they happen at the same time ?
goldenfox [79]

Answer:

Removing Energy: Removing energy will cause the particles in a liquid to begin locking into place. A. Boiling and Evaporation: Evaporation is the change of a substance from a liquid to a gas.

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5 0
3 years ago
Suppose you were asked to find the torque about point p due to the normal force n in terms of given quantities. which method of
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Answer:

T=Lnsin\alpha

Please check the attached

Explanation:

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7 0
3 years ago
Which of these is exhibiting kinetic energy?1) a rock on a mountain ledge2) a space station orbiting Earth 3) a person sitting o
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The answer would be:

A space station orbiting Earth.

7 0
3 years ago
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The cross section of a copper strip is 1.2 mmthick and 20 mm wide. There is a 25-A current through this cross section, with the
Naily [24]

To solve this problem it is necessary to use the concepts related to the Hall Effect and Drift velocity, that is, at the speed that an electron reaches due to a magnetic field.

The drift velocity is given by the equation:

V_d = \frac{I}{nAq}

Where

I = current

n = Number of free electrons

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q = charge of proton

Our values are given by,

I = 25 A

A= 1.2*20 *10^{-6} m^2

q= 1.6*10^{-19}C

N = 8.47*10^{19} mm^{-3}

V_d =\frac{25}{(1.2*20 *10^{-6})(1.6*10^{-19})(8.47*10^{19} )}

V_d = 7.68*10^{-5}m/s

The hall voltage is given by

V=\frac{IB}{ned}

Where

B= Magnetic field

n = number of free electrons

d = distance

e = charge of electron

Then using the formula and replacing,

V=\frac{(2.5)(25)}{(8.47*10^{28})(1.6*10^{-19})(1.2*10^{-3})}

V = 3.84*10^{-6}V

5 0
3 years ago
PLEASE HELP ONLY 5 QUESTIONS
Phantasy [73]
1. b or c
2. c
3. a? or d
4.
5. a
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3 years ago
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