I need to see the diagram in order to answer your question.
This is another one for my "impossible math question" file. All of the answer choices are wrong. (None applies.)
According to the problem statement, the length you have marked "x" in the diagram is 15 inches. If the side length of one of the pavers is "s", then the Pythagorean theorem tells us
s² + (2s)² = 15²
5s² = 225
s² = 225/5 = 45 . . . . . . the area of one square is 45 in² (not 225 in²)
Then
s = √45 = 3√5 . . . . . . . the length of one side is not 5√3
so the perimeter is
p = 4s = 4·3√5 in = 12√5 in ≈ 26.83 in . . . . not 75 inches.
The area of the 6-block L-shaped path is
total area = 6s² = 6·45 in² = 270 in² . . . . not 450 in²
And the total perimeter is 14 sides, so is
total perimeter = 14s = 14·3√5 in = 42√5 in . . . . not 60√3 in
_____
In cases like this where the answer key is incorrect, you might try asking your teacher show the class how to work the problem.
Angle 2 and angle 11 are alternate exterior angles. Line G and line L are parallel lines. Think of them as train tracks. On the outside or exterior of the train tracks is angle 2 and angle 11.
Angle 2 is on the right side of the transversal line, while angle 11 is on the left side of the transversal line.
So this is why they are alternate exterior angles. Because line G and line L are parallel lines, this means the alternate exterior angles are congruent (by the alternate exterior angle theorem).
Since angle 2 is 115 degrees, angle 11 must also be 115 degrees
Answer: C) 115
