Ask question

Ask question

All categories

2 years ago

15

According to her running log, Ariana averaged 4 miles per week last month and 75% less this month. How much did she average this

month?

1 answer:

Umnica [9.8K]2 years ago

3 0

Answer:

She averaged 3 miles per week this month.

Step-by-step explanation:

You just take 75% of 4 and get 3.

You might be interested in

Suppose you have 3 pieces of string measuring 6 inches, 9 inches, and 12 inches. How many unique triangles can you form with the

siniylev [52]

A triangle should have 3 points and 3 sides. Let say that the point is ABC. Then the sides would be AB, AC and BC.
There are 3 strings with a different length that can be put into the sides. Assuming the string can be used once, then the possible way would be:
3!/(1+3-3)!= 3!/1!= 3*2*1= 6 ways

8 0

3 years ago

Jocelyn walks her dog 5 days each week.Each Walk is 2 1/4 miles long. What is the total number of miles that Jocelyn walks her d

igor_vitrenko [27]

Answer:the answer is c

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

For every 3 boys in the class there are 5 girls. If there are 36 boys in gym class, How many girls are there in the gym class ?

SVEN [57.7K]

Answer:

60

Step-by-step explanation:

I divided 36 by 3 got 12 then mutiplyed 12 by 5

7 0

2 years ago

If cos theta = -3/5 in quadrant 2, what is sin theta?

mote1985 [20]

Answer:

hello : sin(θ) = 4/25

Step-by-step explanation:

you know : cos²(θ) + sin²(θ) =1 and : cos(θ) = - 3/5

(-3/5)² + sin²(θ) =1

9/25 + sin²(θ) =1

sin²(θ) =1 -9/25

sin²(θ) = 16/25

sin(θ) = 4/25 or sin(θ) = - 4/25

in quadrant 2 : sin(θ) > 0

so : sin(θ) = 4/25

3 0

3 years ago

Read 2 more answers

The midpoint of AB is M (6,1). If the coordinates of A are (4, 8), what are the coordinates of B?

geniusboy [140]

Answer:

$B = (8,-6)$

Step-by-step explanation:

Given

$A = (4,8)$

$M = (6,1)$ -- Midpoint

Required

Find B

This question will be solved using midpoint formula;

$M(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$

Where

$A(x_1,y_1) = (4,8)$

$M(x,y) = (6,1)$

Substitute these values in the midpoint formula;

$(6,1) = (\frac{4 + x_2}{2},\frac{8+y_2}{2})$

By comparison; we have:

$\frac{4 + x_2}{2} = 6$ -- (1)

$\frac{8 + y_2}{2} = 1$ -- (2)

Solving (1)

$\frac{4 + x_2}{2} = 6$

Multiply both sides by 2

$4 + x_2 = 12$

Subtract 4 from both sides

$x_2 = 8$

Solving (2)

$\frac{8 + y_2}{2} = 1$

Multiply both sides by 2

$8 + y_2 = 2$

Subtract 8 from both sides

$y_2 = -6$

Hence:

$B = (8,-6)$

3 0

3 years ago