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Inga [223]
3 years ago
6

Select all the correct answers. Which expressions are equal to 10^5?

Mathematics
1 answer:
Vlada [557]3 years ago
7 0

Answer:

b, d, and E

Step-by-step explanation:

when you multiplicate all, is the same results

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Write the inverse function for the function, ƒ(x) =1/2x + 4. Then, find the value of ƒ^ -1(4). Type your answers in the box.
Kipish [7]

Answer:

f⁻¹(x) = 2x - 8

f⁻¹(4) = 2 × 4 - 8

f⁻¹(4) = 0

Step-by-step explanation:

f(x) = \frac{1}{2} x + 4\\x = \frac{1}{2} f^{-1}(x) + 4\\x - 4 = \frac{1}{2} f^{-1}(x)\\2x - 8 = f^{-1}(x)\\f^{-1}(x) = 2x - 8

Let's test it

f^{-1}(f(x)) = 2(f(x)) - 8\\f^{-1}(f(x)) = 2( \frac{1}{2}x + 4) - 8\\f^{-1}(f(x)) = \frac{2}{2}x + 8 - 8\\f^{-1}(f(x)) = x

So we do indeed have the inverse function, so using that we can plug in the values requested:

f⁻¹(x) = 2x - 8

f⁻¹(4) = 2 × 4 - 8

f⁻¹(4) = 0

4 0
3 years ago
Please help me asap!
Alchen [17]
UhhhhhhhhhhHHHHHHHHHHHHHHHHH IDK BUT GUESS AND PUT B
5 0
3 years ago
If p<0,q>0 and q=r what statement about is r true
irina [24]

Answer:

hell no

Step-by-step explanation:

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3 0
2 years ago
Angle x and 56 are complementary. What is the value of x?<br> 149<br> 34<br> 56<br> 90
Anni [7]

Answer:

34°

Step-by-step explanation:

90-56=34°

__________

5 0
2 years ago
2.
Gekata [30.6K]

Answer: the system has no solution.

Step-by-step explanation:

\displaystyle\\

\left \{ {{x^2y=16\ \ \ \ \ (1)} \atop {x^2+4y+16=0\ \ \ \ \ (2)}} \right. .\\

Multiply\  both\  sides\  of\  the\  equation\ (2)\   by\  y\  (y\neq 0):\\

x^2y+4y^2+16y=0\\

We\  substitute\  equation\  (1)\  into\  equation\  (2):\\

16+4y^2+16y=0\\

4y^2+16y+16=0\\

4*(y^2+4y+4)=0\\

4*(y^2+2*y*2+2^2)=0\\

4*(y+2)^2=0\\

Divide\  both\  sides\  of\  the \ equation\  by\  4:\\

(y+2)^2=0\\

(y+2)*(y+2)=0\\

So,\ y+2=0\\

y=-2.\\

\displaystyle\\We\  substitute\  the\  value\  of\  y\  into\  equation\  (1):\\x^2*(-2)=16\\Divide\  both\  sides\  of\  the \ equation\  by\  -2:\\x^2=-8\\x^2\geq 0\\ Hence,\ the\ system\ has\ no\ solution.

7 0
1 year ago
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