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Angelina_Jolie [31]
4 years ago
10

(Z-6) divided by 3 for z= 15.9

Mathematics
2 answers:
Ira Lisetskai [31]4 years ago
5 0
(z-6) turns to (15.9-6) which is 9.9 then divide that by 3 and you get 3.3
scoray [572]4 years ago
4 0
Simply plug in \sf{z=15.9} into \sf{\frac{z-6}{3}}

So:

\sf{\frac{15.9-6}{3}}

Simplify that more:

\sf{\frac{9.9}{3}}

And that finally becomes 

\sf{3.3}

So when \sf{z=15.9} the answer will be \boxed{\sf{3.3}}
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You have 8,640 grams of a radioactive kind of cesium. If its half-life is 30 years, how much
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The mass of cesium left afer 120 years if the original mass of cesium is 8640 with an half-life of 30 years,  is 540 grams.

<h3>What is half-life?</h3>

This can be defined as the time taken for half the amount of a radioactive substance to decay.

To calculate the amount of cesium left after 120 years, we use the formua below.

Formula:

  • R' = R/(2^{T/t})............. Equation 1

Where:

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  • T = Total time
  • t = Half-life

From the question,

Given:

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  • t = 30 years

Substitute these values into equation 1

  • R' = 8640/(2^{120/30})
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Hence, The mass of cesium left afer 120 years is 540 grams.

Learn more about half-life here: brainly.com/question/25750315

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