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3 years ago

Please help lots of points rewarded

Mathematics

2 answers:

castortr0y [4]3 years ago

8 0

Answer:

tₙ = 2n² - 3

Step-by-step explanation:

Standard form of a quadratic equation:

y = ax² + bx + c

Apply same for the quadratic sequence:

tₙ = an² + bn + c

Substitute n with 1, 2 and 3 to get the system:

-1 = a*1² + b*1 + c ⇒ a + b + c = -1
5 = a*2² + b*2 + c ⇒ 4a + 2b + c = 5
5 = a*3² + b*3 + c ⇒ 9a + 3b + c = 15

Subtract the first equation from the second and subtract the second equation from the third to get:

3a + b = 6
5a + b = 10

Again subtract the equations to find a:

2a = 4
a = 2

Then find b and c:

b = 3a - 6 = 6 - 6 = 0
c = -1 - a - b = -1 - 2 - 0 = -3

Substitute the coefficients back into the equation of the quadratic sequence:

tₙ = 2n² + 0n + (-3) = 2n² - 3

ololo11 [35]3 years ago

6 0

A of n = 2n^2 - 3
the nth term = 2 times n to the power of 2 minus 3

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Answer:

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