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Rainbow [258]
3 years ago
13

The large rectangle below represents one whole. What percent is represented by the shaded area? (URGENT)

Mathematics
2 answers:
madam [21]3 years ago
7 0

Answer:

40%

[img id="5156800"][/img]

Step-by-step explanation:

Image description: A pie that is split into 5 pieces, similar to the rectangle in the question, except no region is shaded.

1. You see that there are 5 quadrants in the rectangle.

2. You count how many quadrants of the rectangle are shaded in.

3. In the following image there are two shaded quadrants which means 2 out of the 5 quadrants are shaded.

4. In fractions this would equate to 2/5, but this question is asking for percantages.

5. Most of the time percantages are out of 100%, so that is what we'll be basing our answer off of.

6. First we can start with the totoal amount of quadrants, which is 5, and we will divide the 100% by 5, which is 20%.

7. Because there are two shaded areas we would equate each shaded quadrant to 20%, and because there are 2 shaded quadrants we would multiply the number of shaded quadrants by 20%.

8. So we would get 20x2=40

9. By these calculations we would get 40%

10. 40% of the rectangle is shaded.

nikitadnepr [17]3 years ago
4 0

Answer:

40%

Step-by-step explanation:

The whole rectangle is split into 5 parts. Two out of 5 parts are shaded.

Set up a fraction:

\frac{\text{Shaded}}{\text{Whole}}=\frac{2}{5}

Convert into a decimal:

\frac{2}{5}= 0.4

Multiply the decimal by 100 to get the percent:

0.4*100=40

So, forty percent of the rectangle is shaded.

Hope this helps.

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sergeinik [125]

Answer:  \bold{\dfrac{8}{3}}

<u>Step-by-step explanation:</u>

\int\limits^2_0 {x^2} \, dx =\dfrac{x^3}{3}\bigg|^2_0=\bigg(\dfrac{2^3}{3}\bigg)-\bigg(\dfrac{0^3}{3}\bigg)=\dfrac{8}{3}-0=\dfrac{8}{3}

NOTE: Neither the Trapezoidal Rule or Reimann Sums can be used without the number of rectangles (n) you are separating the interval into.  Besides, they only provide an estimate. If you want the EXACT area, you must use integration.

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The sum of the squares of two positive integers is 185. If one integer is 3 less than the other, fine the larger integer.
kari74 [83]

Answer:

\boxed{\sf \ 11 \ }

Step-by-step explanation:

Hi,

let's note the two integers a and b

a^2+b^2=185 \ and \\\\a = b - 3

We are asked to find b

<em>replace a in the first equation</em>

   (b-3)^2+b^2=185\\\\b^2-6b+9+b^2=185\\\\ 2b^2-6b+9-185=0\\\\ 2b^2-6b-176=0\\\\ b^2-3b-88=0\\\\b^2+8b-11b-88=0\\\\b(b+8)-11(b+8)=0\\\\(b-11)(b+8)=0\\\\ b = 11 \ or \ b = -8

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3 0
4 years ago
What are the real and complex solutions of the polynomial equation? x^4-41x^2=-400
tankabanditka [31]
<h3>Answer:</h3>

The real solutions are -5, -4, 4, 5. There are no complex solutions.

<h3>Step-by-step explanation:</h3>

The equation ...

... x^4 -41x^2 +400 = 0

can be factored as ...

... (x^2 -16)(x^2 -25) = 0

... (x -4)(x +4)(x -5)(x +5) = 0

So, all roots are real and are ...

... x ∈ {-5, -4, 4, 5}

_____

These are the values of x that make the factors zero.

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