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2 years ago

Solve with quadratic formula. 4k^2- 20 = k

Mathematics

2 answers:

zvonat [6]2 years ago

5 0

Answer: $k= \frac{1+\sqrt{321} }{8} , \frac{1-\sqrt{321} }{8}$

Step-by-step explanation:

Move all terms to one side.

$4^{2} -20-k=0$

Use the Quadratic Formula.

$k=\frac{1+\sqrt{321} }{8}$ , $k=\frac{1-\sqrt{321} }{8}$

skelet666 [1.2K]2 years ago

3 0

Step-by-step explanation:

4k² - 20 = k

4k² - k - 20 = 0

By quadratic formula :

$x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

x =( 1 ± √80 ) / 8

x = (1 ± 4√5)/8

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AURORKA [14]

To find the cost per yard, divide the cost by the amount:

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Hope this helps.

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3 years ago

REALLY NEED HELP ON THESE 3 MATH QUESTIONS!!! (20 PTS)

hammer [34]

1. x² - 6x + 8
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=(x-4)(x-2)

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7 0

2 years ago

How is the rate 4.5%

vichka [17]

The number in brackets represents the percentage change
1.045
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2 years ago

Which factorization could represent the number of water bottles and weight of each water bottle?

motikmotik

The factorization that could represent the number of water bottles and weight of each water bottle is 12(5x^2 + 4x + 2). Option B

<h3>What is factorization?</h3>

The term factorization has to do with the process of obtaining common factors in an expression. It involves dividing each term in the expression with a factor that is common to all the terms in the expression.

The factorization that could represent the number of water bottles and weight of each water bottle is 12(5x^2 + 4x + 2).

Learn more about factorization:brainly.com/question/19386208

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Missing parts;

Mara carried water bottles to the field to share with her team at halftime. The water bottles weighed a total of 60x2 + 48x + 24 ounces. Which factorization could represent the number of water bottles and weight of each water bottle? 6(10x2 + 8x + 2) 12(5x2 + 4x + 2) 6x(10x2 + 8x + 2) 12x(5x2 + 4x + 2)

8 0

1 year ago

A rectangular plot of farmland will be bounded on one side by a river and on the other three sides by a single-strand electric f

likoan [24]

Step-by-step explanation:

Let x be the length and y be the width of the rectangular plot.

The plot is bounded on one side by a river and on the other three sides by a single-strand electric fence. It means,

x+2y = 1500

x = 1500 - 2y ....(1)

We know that the area of a rectangular plot is given by :

A = xy ....(2)

Put the value of x from equation (1) in (2)

$A=(1500-2y)y\\\\A=1500y-2y^2$ .....(3)

For largest area, differentiate above area equation wrt y.

$\dfrac{dA}{dy}=\dfrac{d}{dy}(1500y-2y^2)\\\\=1500-4y\\\\\text{Put}\ \dfrac{dA}{dy}=0\\\\1500-4y=0\\\\y=\dfrac{1500}{4}\\\\=375$

Put the value of y in equation (1).

x = 1500-2(375)

= 750 m

Put the value of y in equation (3).

$A =1500(375)-2(375)^2\\A=281250\ m^2$

Hence, the largest area is 281250 m² and its dimensions are 750 m and 375 m.

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2 years ago