Bottom half I need help

Apply the square root principle to solve (x-5)^2-40=0

Nitella [24]

Answer: {5 ± 2√10, 5 - 2√10}

Step-by-step explanation: First isolate the binomial squared by adding 40 to both sides to get (x - 5)² = 40.

Next, square root both sides to get x - 5 = ± √40.

Notice that root of 40 can be broken down to 2√10.

So we have x - 5 = ± 2√10.

To get <em>x</em> by itself, add 5 to both sides to get x = 5 ± 2√10.

So our answer is just {5 ± 2√10, 5 - 2√10}.

As a matter of form, the number will always come before the

radical term in your answer to these types of problems.

In other words, we use 5 ± 2√10 instead of ± 2√10 + 5.

4 0

3 years ago

What is the exact area of a circle with a diameter of 20 cm?

Kisachek [45]

Hi there! The answer is 100πcm^2

The radius of a circle can be found by dividing the diameter by 2. In other words : the radius is half of the diameter.
Therefore, the radius of a circle with a diameter of 20 cm is 10 cm.

The exact area of a circle can be found using the following formula:
$a = \pi \times \: {r}^{2} \\ with \\ a = area \\ r = radius$

In order to find our answer, we need to plug in the data from the question.
$a = \pi \: \times {10}^{2} = 100\pi$

Hence, the answer is 100πcm^2.

5 0

3 years ago

HELP PLEASEEE

jeka94

The exact circumference of the circle is $7 \frac{49}{150} k m$