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3 years ago

5

Mrs. Yamaguchi's class weighed the potatoes that they grew in their garden and recorded the data in a table. What are the least

and greatest weights of the potatoes in the data set? (Picture Below)
The least weight is (blank) pounds and the greatest weight is (blank) pounds.

(Please only answer if you know it.) I'll give brainliest to the correct answer!

1 answer:

Natali [406]3 years ago

8 0

Answer:

Least: 1/8

Greatest: 3/4

Step-by-step explanation:

Plz give brainliest

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This is due like right now, please help me!!!!

Varvara68 [4.7K]

$\bold{\huge{\orange{\underline{ Solution }}}}$

$\bold{\underline{ Given \: Rules}}$

<u>The </u><u>sum</u><u> </u><u>of </u><u>the </u><u>number </u><u>in </u><u>each </u><u>of </u><u>the </u><u>four </u><u>rows </u><u>is </u><u>the </u><u>same </u>
<u>The </u><u>sum </u><u>of </u><u>the </u><u>numbers </u><u>in </u><u>each </u><u>of </u><u>the </u><u>three </u><u>columns </u><u>is </u><u>the </u><u>same</u>
<u>The </u><u>sum </u><u>of </u><u>any </u><u>row </u><u>does </u><u>not </u><u>equal </u><u>the </u><u>sum </u><u>of </u><u>any </u><u>column </u>

$\bold{\underline{ Let's \: Begin}}$

<u>According </u><u>to </u><u>the </u><u>Second</u><u> </u><u>rule </u><u>:</u><u>-</u>

$\sf{ 75+b+83=76+80+d=a+81+85+78+c+e }$

$\sf{ 158 + b = 156 + d = 166 + a = 78 + c + e ...(1)}$

<u>According </u><u>to </u><u>the </u><u>first </u><u>rule </u><u>:</u><u>-</u><u> </u>

$\sf{ 75+76+a+78 = b+80+81+c = 83+86+d+e}$

$\sf{ 229 + a = 161 + b + c = 168 + d + e ...(2)}$

<u>From </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>we </u><u>got </u><u>:</u><u>-</u>

$\sf{ 158 + b = 166 + a, 156 + d = 166 + a }$

$\sf{ b = 166 - 158 + a, d = 166 - 156 + a }$

$\sf{ b = 8 + a, d = 10 + a ...(3)}$

<u>Subsitute </u><u>(</u><u>3</u><u>)</u><u> </u><u>in </u><u>(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>:</u><u>-</u>

$\sf{229+a = 161+8+a+c = 168+10+a+e}$

$\sf{ 229+a = 169+a+c = 178+a+e}$

<u>We</u><u> </u><u>can </u><u>write </u><u>it </u><u>as </u><u>:</u><u>-</u>

$\sf{ 229+a = 169+a+c \:or\:229+a = 178+a+e}$

$\sf{ c = 299-169+a-a\:or\:e = 229-178+a-a}$

$\sf{ c = 60 \: and \: e = 51 }$

<u>Subsitute </u><u>the </u><u>value </u><u>of </u><u>c </u><u>and </u><u>e </u><u>in </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>

$\sf{ 158 + b = 156 + d = 166 + a = 78 + 60 + 51 }$

$\sf{ 158 + b = 156 + d = 166 + a = 189}$

<u>Now</u><u>, </u>

$\sf{ For \: b, 158 + b = 189 }$

$\sf{ b = 189 - 158 }$

$\sf{ b = 31}$

$\sf{ For \: d , 156 + b = 189 }$

$\sf{ d = 189 - 156 }$

$\sf{ d = 33}$

$\sf{ For \: a, 166 + a = 189 }$

$\sf{ a = 189 - 166 }$

$\sf{ a = 23 }$

Hence, The value of a, b, c, d and e is 23, 31 ,60 ,33 and 51 .

8 0

2 years ago

Genrish500 [490]

Answer:

Explanation:

3 0

3 years ago

Read 2 more answers

Simplify by factoring. What are the excluded values? Choose all that apply.

makvit [3.9K]

Answer:

x = -2

x = 8

Step-by-step explanation:

Excluded values are the ones which make the denominator zero

3x² + x - 10

3x² + 6x - 5x - 10

3x(x + 2) - 5(x + 2)

(x + 2)(3x - 5)

x² - 6x - 16

x² - 8x + 2x - 16

x(x - 8) + 2(x - 8)

(x - 8)(x + 2)

[(x + 2)(3x - 5)] ÷ [(x - 8)(x + 2)]

(3x - 5)/(x - 8)

So excluded values are 8, -2

6 0

3 years ago

Determine whether 81a2 − 25z6 is a difference of two squares. If so, factor it. If not, explain why.

aev [14]

81 a² - 25 $z^{6}$ is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)

Step-by-step explanation:

The difference of two squares is a binomial of two terms each term is a square and the sign between the two terms is (-), its factorization is the product of two identical binomials with different middle signs

a² - b² is a difference of two squares
a² - b² = (a + b)(a - b)

∵ The binomial is 81 a² - 25 $z^{6}$

∵ $\sqrt{81}$ = 9

∵ $\sqrt{a^{2} }$ = a

∴ $\sqrt{81a^{2}}=9a$

∵ $\sqrt{25}$ = 5

∵ $\sqrt{z^{6}}$ = z³

∴ $\sqrt{25z^{6}}=5z^{3}$

- The two terms have square root

∵ The sign between them is (-)

∴ 81 a² - 25 $z^{6}$ is a difference of two squares

∵ Its factorization is two identical brackets with different

middle signs

∵ 81 a² = 9a × 9a

∵ 25 $z^{6}$ = 5z³ × 5z³

- The terms of the two brackets are 9a and 5z³

∴ 81 a² - 25 $z^{6}$ = (9a + 5z³)(9a - 5z³)

81 a² - 25 $z^{6}$ is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)

Learn more:

You can learn more about the difference of two squares in brainly.com/question/1414397

#LearnwithBrainly

7 0

3 years ago

What is the correct answer for the problem 3.12 x 4.0

ch4aika [34]

Hi Brielle the correct answer to your question is 3.12 x 4.0 = 12.48

7 0

2 years ago

Read 2 more answers