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3 years ago

Which pairs of polygons are similar? Select each correct answer.

Mathematics

2 answers:

padilas [110]3 years ago

8 0

What was the answer please help me

kvasek [131]3 years ago

5 0

Answer: The first and fourth pair of polygons are similar.

Step-by-step explanation:

If two polygons are similar then their corresponding sides are proportional.

Let's check

In the first pair there are two rectangles and their dimensions are proportional as

$\frac{22}{13.75}=\frac{16}{10}=1.6$

In the second pair there are right triangles but their dimensions are not proportional as

$\frac{18}{8}=2.25$ and $\frac{30}{17}=1.76$

In the third pair there is one isosceles triangle and other is equilateral triangle, which can not be similar as they have different type of triangles.

In the fourth pair there are two right trapezoid and their dimensions are proportional as

$\frac{7.5}{3}=\frac{30}{12}=\frac{12.5}{5}=\frac{20}{8}=2.5$

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mario62 [17]

Answer:

$(x-7)^2+(y-5)^2=1$

Step-by-step explanation:

The two things that are required to formulate the equation of the circle is the center coordinate and the radius of the circle!

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The center of the circle always lies at the midpoint of the endpoints of its diameter: Let's call the endpoints A(6,5) and B(8,5).

Using the midpoint formula we'll get:

$(x_m, y_m) = \left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

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$(x_m, y_m) = (7,5)$

This is the center coordinate of our circle.

Radius:

The radius of the circle is the distance from the center of the circle to any of the endpoints of the diameter (A or B)

We can use the distance formula:

$r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$r = \sqrt{(x_1-x_m)^2+(y_1-y_m)^2}$

$r = \sqrt{(6-7)^2+(5-5)^2}$

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Equation of the circle:

The equation is written as:

$(x-a)^2+(y-b)^2=r^2$

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Step-by-step explanation:

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