Which pairs of polygons are similar? Select each correct answer.

Mathematics

2 answers:

padilas [110]3 years ago

8 0

What was the answer please help me

kvasek [131]3 years ago

5 0

Answer: The first and fourth pair of polygons are similar.

Step-by-step explanation:

If two polygons are similar then their corresponding sides are proportional.

Let's check

In the first pair there are two rectangles and their dimensions are proportional as

$\frac{22}{13.75}=\frac{16}{10}=1.6$

In the second pair there are right triangles but their dimensions are not proportional as

$\frac{18}{8}=2.25$ and $\frac{30}{17}=1.76$

In the third pair there is one isosceles triangle and other is equilateral triangle, which can not be similar as they have different type of triangles.

In the fourth pair there are two right trapezoid and their dimensions are proportional as

$\frac{7.5}{3}=\frac{30}{12}=\frac{12.5}{5}=\frac{20}{8}=2.5$

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Solve the following system of equations. Enter the y-coordinate of the solution. Round your answer to the nearest tenth.

lakkis [162]

$\sf 5x+2y=21$
$\sf -2x+6y=-34$

We could solve for 'x' in the 2nd equation and then plug that into the first equation for 'x' and solve for 'y':

$\sf -2x+6y=-34$

Subtract 6y to both sides:

$\sf -2x=-6y-34$

Divide -2 to both sides:

$\sf x=3y+17$

Plug in 3y + 17 for 'x' in the first equation:

$\sf 5x+2y=21$

$\sf 5(3y+17)+2y=21$

Distribute 5:

$\sf 15y+85+2y=21$

Combine like terms:

$\sf 17y+85=21$

Subtract 85 to both sides:

$\sf 17y=-64$

Divide 17 to both sides:

$\boxed{\sf y\approx -3.8}$

This is the y-coordinate of the solution.

5 0

2 years ago

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Blizzard [7]

the given figure is a rhombus, so it's area =

$\frac{1}{2} \times \: d1 \times d2$