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Westkost [7]
3 years ago
14

Which order shows decreasing wavelength?

Chemistry
2 answers:
erik [133]3 years ago
6 0

Answer:

C

Explanation:

just did it

blagie [28]3 years ago
4 0

Answer:

The answer is c radio --> infrared --> ultraviolet --> gamma

Explanation:

I just did it

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When combined with an oxidizing agent (such as fluorine), will metals tend to lose or gain electrons?
Scorpion4ik [409]

When combined with an oxidizing agent metals tend to Lose  electrons

The loss of electrons is referred to as oxidation. Each of the elements (for example, chlorine) might theoretically accept electrons from another element and be ionised as a result (e.g. Cl-). That is, they are all potentially oxidising agents.

<h3>Is fluorine an oxidizing agent?</h3>

Fluorine is such a strong oxidizer that solution reactions are impossible.

Chlorine can accept electrons from both bromide ions and iodide ions. Bromine and iodine are unable to recoup the electrons released by the chloride ions.

This suggests that chlorine is a more potent oxidising agent than bromine or iodine.

Similarly, bromine is a stronger oxidizer than iodine. Bromine may steal electrons from iodide ions to form iodine; iodine, however, cannot recoup those electrons from the ensuing bromide ions.

learn more about oxidizing agent refer:

brainly.com/question/9064518

#SPJ4

4 0
2 years ago
Please help me with this question
yKpoI14uk [10]

The mass of oxygen is 236.4 g.

Explanation:

To find the mass of oxygen in 325 g of carbon dioxide (CO₂) we follow the next algorithm.

First we calculate the molar weight of carbon dioxide:

molar weight of CO₂ = molar weight of carbon × 1 + molar weight of oxygen × 2

molar weight of CO₂ = 12 × 1 + 16 × 2 = 44 g/mole

Now we devise the following reasoning:

if in        44 g of CO₂ there are 32 g of oxygen

then in  325 g of CO₂ there are X g of oxygen

X = (32 × 325) / 44 = 236.4 g oxygen

Learn more about:

molar weight

brainly.com/question/9883301

#learnwithBrainly

6 0
3 years ago
I would appreciate your help! Due today! ( I don't know if this is even chemistry)
Vinil7 [7]

Answer:

6+69

Explanation:

6 0
3 years ago
Read 2 more answers
For the following reaction if you have 13.2g of CO and 42.7g of Fe2O3, which is the limiting reagent with regards to the Fe prod
MrRissso [65]

Answer: CO is a limiting reagent with regards to the Fe production.

Explanation:

Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(s)+3CO_2(g)

Moles of CO = \frac{\text{mass of CO}}{\text{molar mass of CO}}=\frac{13.2 g}{28 g/mol}=0.4714 mol

moles of Fe_2O_3=\frac{\text{mass of} Fe_2O_3}{\text{molar mass of}Fe_2O_3}=\frac{42.7 g g}{159.7 g/mol}=0.2673 mol

According to reaction , 3 mole of CO reacts with 1 mole of Fe_2O_3 then , 0.4714 moles of CO will react with : \frac{1}{3}\times 0.4714 moles of Fe_2O_3 that is 0.1571 moles.

0.4714 moles of CO will react with 0.1571 moles of Fe_2O_3 which means that CO is present in limited amount acting as limiting reagent.

Mole remaining of Fe_2O_3 = 0.2673 mol - 0.1571 mol = 0.1102 mol

Hence, CO is a limiting reagent and  Fe_2O_3 is an excessive reagent.

8 0
4 years ago
The oxidation of sulfur dioxide by oxygen to sulfur trioxide has been implicated as an important step in the formation of acid r
Igoryamba

Answer:

The value of the equilibrium constant K_p at this temperature is 3.42.

Explanation:

Partial pressure of the sulfur dioxide =p_1=0.564 atm

Partial pressure of the oxygen gas =p_2=0.102 atm

Partial pressure of the sulfur trioxide =p_3=0.333

2 SO_2(g) + O_2(g)\rightleftharpoons 2 SO_3(g)

The expression of an equilibrium constant is given by :

K_p=\frac{(p_3)^2}{(p_1)^2\times p_2}

K_p=\frac{(0.333 atm)^2}{(0.564 atm)\times (0.102 atm)}=3.42

The value of the equilibrium constant K_p at this temperature is 3.42.

7 0
4 years ago
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