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Tomtit [17]
3 years ago
6

Assume you add 5 g of Nacl to a beaker and add water until the volume of the solution reaches 4 L. Calculate the concentration o

f salt in water in g/L and mol/L.
Chemistry
1 answer:
jolli1 [7]3 years ago
8 0

Answer:

1.25 g/L.

0.0214 mol/L.

Explanation:

Concentration in g/L = 5/4

= 1.25 g/L (answer).

As for  mol / L we need to know the molar mass of salt.

It is 22.99 + 35.45 = 58.44.

So in mol/L it is  1.25 / 58.44

= 0.0214 mol/L.

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Answer: A. are relatively far apart

Explanation:

Compressbility is the ability of compound to reduce in size when pressure is applied.

Gaseous state is a state in which the particles are loosely arranged and have a lot of space between them. Thus molecules can be easily compressed.

They have highest kinetic energy. This state has indefinite volume as well as shape.  The molecules in the gaseous state move faster with an increase in temperature as the kinetic energy increases with increase in temperature.

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D. The total mass of the reactants equals the total mass of the

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What is the entropy change for the freezing process of 1 mole of liquid methanol at its freezing temperature (–97.6˚C) and 1 atm
Rudiy27

Answer : The value of change in entropy for freezing process is, -18.07 J/mol.K

Explanation :

Formula used :

\Delta S=\frac{\Delta H_{freezing}}{T_f}

where,

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As we know that:

\Delta H_{fus}=-\Delta H_{freezing}=-3.17kJ/mol=-3170J/mol

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Now put all the given values in the above formula, we get:

\Delta S=\frac{\Delta H_{freezing}}{T_m}

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Therefore, the value of change in entropy for freezing process is, -18.07 J/mol.K

4 0
4 years ago
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