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3 years ago

5

What is the solution to log Subscript 5 Baseline (10 x minus 1) = log Subscript 5 Baseline (9 x + 7) x = six-nineteenths x = eig

ht-nineteenths x = 7 x = 8

2 answers:

KiRa [710]3 years ago

5 0

Answer:

x=8

Step-by-step explanation:

on edge

S_A_V [24]3 years ago

5 0

Answer:

8

Step-by-step explanation:

on edge

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Assuming the series is

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We have

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|$

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If $x=1$ , then the series is a scaled harmonic series, which we know diverges.

On the other hand, if $x=-1$ , by the alternating series test we can show that the series converges, since

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Step-by-step explanation:

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