Question

Identify the equation of the circle B that passes through (5,1) and has center (3,0).

Answer 1

Answer:

Are you saying look for the slope? because if so can help

Step-by-step explanation:

Answer 2

Answer:   (x − 3)2 +  y2 = 5

a. (x + 3)2 +  y2 = 5

b. (x − 3)2 +  y2 = 25

c. (x − 3)2 +  y2 = 5

d. (x + 5)2 + ( y + 1)2 = 25

Step-by-step explanation:

Begin by determining the length of the radius for the circle. A radius is a line segment from the center of the circle to any point on the circle. Find the length of the radius using the Distance Formula.

r= √(x2 − x1)2 + (y2 − y1)2

Substitute the given values for the center of the circle and the point on the circle into the distance formula and solve for r.

r= √( 5− 3)2 + (1 − 0)2

= √22 + 12

= √4 + 1

= √5

So, the length of the radius is √5 units.

The equation of a circle with center (h, k) and radius r is (x − h)2 + (y − k)2 = r2. Substitute the value for the radius and the coordinates of the center of the circle into the equation.

(x − 3)2 +(y − 0)2 = (√5)2

Simplify.

(x − 3)2 + y2 = 5                                                                                            Therefore, the equation of the circle B that passes through (5, 1) and has center (3, 0) is (x − 3)2 +y2 = 5.