Oxygen has 8 protons and 10 electrons due to the addition of 2 electrons, determined from the ion charge. Likewise an ion of potassium has 19 protons and 18 electrons. Charge on fluorine would be -1 and charge on calcium would be +2. Atomic number is the same as the number of protons, so it would be 6, the mass number is the sum of protons and neutrons which would be 13, and the charge is 0, as it is an atom and not an ion.

5 0

3 years ago

Sickle-cell anemia is a genetic disease that causes red blood cells to have an odd shape. The odd shape prevents the blood cells

vredina [299]

"Normal red blood cells are rounded and disk-shaped. In sickle cell anemia, some red blood cells become deformed, so they look like sickles used to cut wheat. These unusually shaped cells give the disease its name. Sickle cell anemia is one of a group of disorders known as sickle cell disease."

8 0

2 years ago

The rock in a particular iron ore deposit contains 82 % Fe2O3 by mass. How many kilograms of the rock must be processed to obtai

Zinaida [17]

Answer:

Mass of rock = 4533.4 kg

Explanation:

Percent composition is percentage by the mass of element present in the compound.

Given that the $Fe_2O_3$ is 82 % by mass.

It means that 82 kg of $Fe_2O_3$ is present in 100 kg of rock

To find the mass of rock which contains 2600 kg of iron

2600 kg = 2600*1000 g

2 moles of iron are present in 1 mole of $Fe_2O_3$

Molar mass of iron = 55.845 g/mol

Mass of 2 moles = 55.845 * 2 = 111.69 g/mol

Molar mass of $Fe_2O_3$ = 159.69 g/mol

It means,

111.69 g of iron are present in 159.69 g of $Fe_2O_3$

1 g of iron is present in 159.69/111.69 g of $Fe_2O_3$

2600*1000 g is present in (159.69/111.69)*2600*1000 g of $Fe_2O_3$

Mass of $Fe_2O_3$ = 3717378.47 g =3717.38 kg

Thus,

82 kg of $Fe_2O_3$ is present in 100 kg of rock

1 kg of $Fe_2O_3$ is present in 100/82 kg of rock

3717.38 kg of $Fe_2O_3$ is present in (100/82)*3717.38 kg of rock

Mass of rock = 4533.4 kg

5 0

3 years ago

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