<span>I believe that its
Cu</span>
Your answer is going to be A, because it was shoved harder, it will go faster
Answer:
The oxidation state of N in the KNO3 is +5
Explanation:
Oxidation rules:
1. Oxygen is -2, unless in peroxides.
2. Group 1 metals = +1
3. Group 2 metals = +2
4. If the molecule is neutral, all of the oxidation numbers have to add up to zero.
5. If the molecule is charged, all of the oxidation numbers have to add up to the charge of the molecule.
So, the given formula represents the salt compound formula unit of potassium nitrate: KNO3
The formula unit is uncharged.
From our rules, we know that,
O = -2
And we can find K on the periodic table, in the first group, thus giving it a +1 charge. Now let's put it all together.
K = +1
N = x
O = -2
Let's take into account the number of atoms of each element we have and make an equation since we know everything has to add up to zero since the molecules are neutral.
+1 +x+3 (-2) = 0 (notice we multiplied 3 by -2 because in the formula we have 3 atoms of oxygen with -2 charge each)
x - 5 = 0
x = 5
Therefore, the oxidation number of N in KNO3 is +5.
As per the law of constant composition, a given sample will always contain the same number of elements that combine in the same mass proportion.
Therefore if a sample of 13.97 g of NaBr contains 22.39 % of Na by mass then, a sample of 5.75 g of NaBr would also contain 22.39% Na by mass
Hence:
Mass of Na = 5.75 g * 22.39/100 = 1.287 g
5.75 g of NaBr would contain 1.29 g of Na
Answer:
The answer to your question is V2 = 333.9 ml
Explanation:
Data
Pressure 1 = P1 = 1.977 atm
Volume 1 = V1 = 517.4 ml
Pressure 2 = P2 = 3.063 atm
Volume 2 = V2 = ?
Process
To solve this problem use Boyle's law
P1V1 = P2V2
-Solve for V2
V2 = P1V1/P2
-Substitution
V2 = (1.977 x 517.4) / 3.063
-Simplification
V2 = 1022.9 / 3.063
-Result
V2 = 333.9 ml
