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3 years ago

There are 34 questions on a test. John answers 22 correctly. What is Johns percent error?

Chemistry

1 answer:

VARVARA [1.3K]3 years ago

4 0

Answer:

35 . 29%

Explanation:

no. of questions in test =34

no. of questions answered correctly =22

therefore, no. of questions answered incorrectly =34 - 22

=12

error percentage = 12/34 * 100

=35 .29 %

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Help pls you get 22 points if you answer me

snow_tiger [21]

Answer:

the 2nd one

Explanation:

All other symbols are for Mathematics.

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2 years ago

The chemical breakdown of enormous quantities of organic material buried in the sedimentary rocks has produced gas.

Lelu [443]

The chemical breakdown of enormous quantities of organic material buried in the sedimentary rocks has produced ethane gas.

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3 years ago

When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezin

loris [4]

The given question is incomplete. The complete question is:

When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.

Answer: The vant hoff factor for sodium chloride in X is 1.9

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=8.2^0C$ = Depression in freezing point

$K_f$ = freezing point constant

i = vant hoff factor = 1 ( for non electrolyte)

m= molality = $\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9$

$8.2^0C=1\times K_f\times 1.9$

$K_f=4.32^0C/m$

Now Depression in freezing point for sodium chloride is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=20.0^0C$ = Depression in freezing point

$K_f$ = freezing point constant

m= molality = $\frac{136g\times 1000}{950g\times 58.5g/mol}=2.45$

$20.0^0C=i\times 4.32^0C\times 2.45$

$i=1.9$

Thus vant hoff factor for sodium chloride in X is 1.9

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2 years ago

How do i find the mole of something?

nikklg [1K]

To find the mole of a substance, you take the mass divided by the molar mass of that substance~

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3 years ago

Read 2 more answers

The mass of solute per 100 mL of solution is abbreviated as (m/v). Mass is not technically the same thing as weight, but the abb

Talja [164]

The mass of solute per 100 mL of solution is abbreviated as (m/v). Mass is not technically the same thing as weight, but the abbreviation (w/v) is also common. 262 grams of sucrose are needed to make 655 mL of a 40.0% (w/v) sucrose solution

<h3>Define Solute</h3>

A solute is a material that dissolves in a solution. The amount of solvent present in fluid solutions is greater than the amount of solute. The two most common examples of solutions in daily life are salt and water. Salt is the solute because it dissolves in water.

<h3>forms of ratios for product concentration or yield:-</h3>

w/v:- Weight by volume or weight per volume are the terms used. Any solid compound's concentration in a liquid can be calculated using it. It is measurable in gm/ml.

Weight by weight ratio is referred to as w/w.It is employed to determine the final yield of the compound obtained from the starting compound. as in —mg/—gm.

It provides the real yield of the substance or item.

Volume/volume. It is used to specify a liquid's composition or percent in a liquid compound.

using w/v we can calculate the weight of sucrose:-

40.0% means 40 g sucrose/ 100 g solution

40.0g sucrose x (655/100)=grams of sucrose

262 grams of sucrose are needed to make 655 mL of a 40.0% (w/v) sucrose solution.

Learn more about Solute here:-

brainly.com/question/14397121

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2 years ago