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insens350 [35]
3 years ago
14

There are 34 questions on a test. John answers 22 correctly. What is Johns percent error?

Chemistry
1 answer:
VARVARA [1.3K]3 years ago
4 0

Answer:

35 . 29%

Explanation:

no. of questions in test =34

no. of questions answered correctly =22

therefore, no. of questions answered incorrectly =34 - 22

=12

error percentage = 12/34 * 100

=35 .29 %

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How much water should be added to 85 mL of 0.45 M HCI to reduce the concentration to 0.20 M?
valkas [14]

Answer:

106.25 mL

Explanation:

For this, we can use

C1×V1=C2×V2

C1 = 0.45

V1 = 85

C2= 0.20

V2= ?

0.45 × 85 = 0.20 × V2

V2= (0.45 × 85)/0.20

V2=191.25mL

To find the amount of water added, subtract V1 from V2

191.25 - 85 =106.25mL

8 0
3 years ago
What is a chemical bond?
antoniya [11.8K]
The answer is A. when electrons are shared between atoms
7 0
2 years ago
Looking at the same nonmetal group on the periodic table, how does the reactivity of an element in period 2 compare to the react
N76 [4]

Answer:

The period 2 element would be more reactive because the attractive force of protons is stronger when electrons are attracted to a closer electron shell.

Explanation:

Nonmetals want to add more electrons to their valence electron shell. Elements in period 2 have their valence shell closer their nucleus, then they are more reactive than period 4 elements.

6 0
3 years ago
Barbiturates are synthetic drugs used as sedatives and hypnotics. Barbital ( = 184.2 g/mol) is one of the simplest of these drug
DanielleElmas [232]

Answer:

118.75°C is the boiling point of a solution.

Explanation:

Mass of the solute that is barbiturates = 42.5 g

Molar mass of a solute = 184.2 g/mol

Moles of solute = \frac{42.5 g}{184.2 g/mol}=0.2307 mol

Mass of the solvent that acetic acid = 825 g = 0.825 kg

molality=\frac{\text{Moles of solute}}{\text{Mass of solvent}}

Molality of the solution (m):

m=\frac{0.2307 mol}{0.825 kg}=0.2796 m

Elevation in boiling point is given as:

\Delta T_b=i\times K_b\times m

i = 1 (organic compound)

=1\times 3.07^oC/m\times 0.2796 m=0.8585^oC

\Delta T_b=T_b-T

T_b = Boiling temperature of solution.

T = boiling temperature of solvent that is acetic acid=117.9°C

0.8585^oC=T_b-117.9^oC

T_b=118.75 ^oC

118.75°C is the boiling point of a solution.

6 0
3 years ago
Consider the dissolution of ammonium nitrate. 1.25 g of amminum nitrate is dissolved in enough water to make 25.0 mL of solution
Mrac [35]

Answer:

\Delta H=-0.02\ kJ

Explanation:

The expression for the calculation of the enthalpy change of a process is shown below as:-

\Delta H=m\times C\times \Delta T

Where,

\Delta H  is the enthalpy change

m is the mass

C is the specific heat capacity

\Delta T  is the temperature change

Thus, given that:-

Mass of ammonium nitrate = 1.25 g

Specific heat = 4.18 J/g°C

\Delta T=21.9-25.8\ ^0C=-3.9\ ^0C

So,

\Delta H=-1.25\times 4.18\times 3.9\ J=-20.3775\ J

Negative sign signifies loss of heat.

Also, 1 J = 0.001 kJ

So,

\Delta H=-0.02\ kJ

5 0
3 years ago
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