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Stells [14]
3 years ago
10

!!!!!!!!!!! Help (Measuring Angles)

Mathematics
1 answer:
lana [24]3 years ago
3 0

Answer:

Angle DGF = DEF

Step-by-step explanation:

Since all the angles are congruent in the diagram and the hypothenuses are both congruent, it makes the other triangle, DEF congruent to DGF.

In other words, sense all 3 angles are congruent and they share a side, DEF is congruent to DGF.

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create a linear equation with the number of hexagons n to the total number of sides T. The determine the number of sides if ther
Margaret [11]

Answer:hbhbhb

Step-by-step explanation:nubby,,,,,

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5 0
3 years ago
It was reported that 23% of U.S. adult cellphone owners called a friend for advice about a purchase while in a store. If a sampl
leva [86]

Answer:

P(X=7)

And using the probability mass function we got:

P(X=7)=(15C7)(0.23)^7 (1-0.23)^{15-7}=0.0271  

Step-by-step explanation:

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=15, p=0.23)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And we want to find the following probability:

P(X=7)

And using the probability mass function we got:

P(X=7)=(15C7)(0.23)^7 (1-0.23)^{15-7}=0.0271  

5 0
3 years ago
On a piece of paper, sketch △ABC with m∠A=30° , m∠B=60° , and m∠C=90° . Which statements about the triangle are true? Select eac
gladu [14]

Answer:

Step-by-step explanation:i dont know duuu

6 0
3 years ago
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
PLEASE ANSWER IT'S IN THE PICTURE I WILL MARK BRAINLIEST IF YOU'RE CORRECT!
harkovskaia [24]

Answer:

It is possible for a set of data values to have more than one mode. If there are two data values that occur most frequently, we say that the set of data values is bimodal. If there is no data value or data values that occur most frequently, we say that the set of data values has no mode.

Step-by-step explanation:

7 0
3 years ago
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