3 years ago

Find the 9th term geometric sequence 1,1/2,1/2^2

Mathematics

1 answer:

valentinak56 [21]3 years ago

3 0

Answer: $t_9=\dfrac{1}{2^8}$

<u>Step-by-step explanation:</u>

$t_n=t_1\times r^{n-1}\\\\Given: t_1=1,\quad r=\dfrac{1}{2}\\\\\\t_9=1\times\bigg(\dfrac{1}{2}\bigg)^{9-1}\\\\\\.\quad =\large\boxed{\dfrac{1}{2^8}}$

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