if the diameter of a circle is 15, its radius is half that or 7.5.
![\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=7.5 \end{cases} A=\pi (7.5)^2\implies A=56.25\pi \implies \stackrel{\pi =3.14}{A=176.625}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D7.5%20%5Cend%7Bcases%7D%20A%3D%5Cpi%20%287.5%29%5E2%5Cimplies%20A%3D56.25%5Cpi%20%5Cimplies%20%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7BA%3D176.625%7D%20)
<span>Draw a regular hexagon. Connect the center to each of the six vertices. Thus, you have six triangles, each with base 10.. The apothem is the height of each triangle. Then the area of each triangle is (1/2)(10)(12) = 60. You have six triangles so the aarea of the hexagon is 6*60 = 360.</span>
Hey! Hopefully this helped :)
Answer:
Option B
Step-by-step explanation:
By applying Pythagoras theorem in the given right triangle,
(Hypotenuse)² = (leg 1)² + (leg 2)²
By substituting the values in the given expression,
7² = x² + 2²
49 = x² + 4
x² = 49 - 4
x² = 45
x = √45
x = 3√5
x = 6.7 ft
Option B will be the correct option.
