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3 years ago

A boy drops a coin down a well that is 225 m deep. How long does it take the coin to hit the bottom of the well? please help

1 answer:

8 0

<span>It takes 6.78 seconds for the coin to hit the bottom of the well. We can use the equation h = 0.5gt^2, where h is the height of the coin, g is the gravitational constant of 9.8m/s^2, and t is the time is takes for the coin to hit the bottom of the well. Solve for t to obtain 6.87 seconds.</span>

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17. ____ Objects with more mass have

AnnZ [28]

a. more gravity

This is the answer.

5 0

3 years ago

An 80kg sled rider starts sledding down a 100m hill from rest. If her final velocity is 15m/s, what is he acceleration down the

krok68 [10]

Given :

An 80kg sled rider starts sledding down a 100m hill from rest. If her final velocity is 15m/s.

To Find :

The acceleration down the hill.

The force needed for that kind of acceleration.

Solution :

By equation of motion :

$v^2 -u^2 = 2as\\\\a = \dfrac{v^2-u^2}{2s}\\\\a = \dfrac{15^2 -0^2}{2\times 100}\\\\a = 1.125\ m/s^2$

Force required is, F = ma

F = 80×1.125 N

F = 90 N

Hence, this is the required solution.

6 0

3 years ago

PART ONE

Korvikt [17]

Answer:

1) 460.5 N

2) 431.7 N

Explanation:

Draw a free body diagram. There are four forces on the hammer:

Applied force 62.5 N in the +x direction, 30 cm from the ground

Reaction force Rᵧ in the +y direction, at the point of contact

Reaction force Rₓ in the +x direction, at the point of contact

Reaction force F at 31° from the vertical, 4.75 cm to the left of the point of contact

Part One

To find F, sum the moments about the point of contact:

∑τ = Iα

(62.5 N) (30 cm) − (F cos 31°) (4.75 cm) = 0

F = 460.5 N

Part Two

To find Rₓ and Rᵧ, sum the forces in the x and y directions.

∑Fₓ = ma

62.5 N − F sin 31° + Rₓ = 0

Rₓ = 174.7 N

∑Fᵧ = ma

-F cos 31° + Rᵧ = 0

Rᵧ = 394.7 N

The net reaction force at the point of contact is:

R = √(Rₓ² + Rᵧ²)

R = 431.7 N

7 0

3 years ago

A pitcher delivers a fast ball with a velocity of 43 m/s to the south. the batter hits the ball and gives it a velocity of 51 m/

hoa [83]

Assuming north as positive direction, the initial and final velocities of the ball are:
$v_i=-43 m/s$ (with negative sign since it is due south)
$v_f=+51 m/s$
the time taken is $t=1.0 ms=0.001 s$ , so the average acceleration of the ball is given by
$a= \frac{v_f-v_i}{t}= \frac{51 m/s-(-43 m/s)}{0.001 s}=9.4 \cdot 10^4 m/s^2$
And the positive sign tells us the direction of the acceleration is north.

4 0

3 years ago

Can someone please help

rosijanka [135]

Answer:

could you probably expand on the question?

Explanation:

6 0

3 years ago