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puteri [66]
3 years ago
5

Un auto alcanza una velocidad de 54km/hrs, en 10 segundos al partir de reposo ¿Cuál fue su aceleración?

Physics
1 answer:
Alborosie3 years ago
4 0

Answer: 1.5\ m/s^2

Explanation:

Given

velocidad v=54\ km/h

tiempo tomado t=10\ s

Convertir km/h en m/s

\Rightarrow 54\ km/h\equiv 15\ m/s

La aceleración está dada por la tasa de cambio de velocidad

\Rightarrow a=\dfrac{v}{t}\\\\\Rightarrow a=\dfrac{15}{10}\\\\\Rightarrow a=1.5\ m/s^2

Por tanto, la aceleración es 1.5\ m/s^2

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Give three factors which are responsible for the vanishing forest ​
slava [35]

Answer:

1. Huge wildfires

2. Deforestation

3. Reduced amount of aforestation, etc

5 0
4 years ago
The electrons lost from chlorophyll photooxidation are replaced by the oxidation of water. how many electrons are generated from
White raven [17]

There are 2 electrons generated from the oxidation of one water molecule.

<h3>Describe photooxidation.</h3>

The process of a substance interacting with oxygen or losing electrons from chemical species under the influence of light is known as photooxidation. Photooxidation happens in plants when there is environmental stress. It is called photooxidative stress as a result. Reactive oxygen species are produced by the absorption of excess excitation energy in plant tissues. Chloroplasts are harmed by the accumulation of these reactive oxygen species, which is a damaging process in plants. High-intensity light and little CO_{2} are the two conditions that cause this photooxidative stress to occur most frequently. It is a procedure that requires light. Photorespiration in C_{3} plants guards against photooxidation.

To know more about Photooxidation visit:

brainly.com/question/14788790

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3 0
1 year ago
A 63 gg ice cube can slide without friction up and down a 30∘30∘ slope. The ice cube is pressed against a spring at the bottom o
tatiyna

Given Information:

slope angle = θ = 30°

spring constant = k = 30 N/m

compressed length = x = 10 cm = 0.10 m

mass of ice cube = m = 63 g = 0.063 kg

Required Information:

distance traveled by ice cube = d = ?  

Answer:

distance traveled by ice cube = 0.48 m

Explanation:

Using the the principle of conversation of energy, the following relation holds true for this case,

mgh = 1/2*kx²

h = 1/2*kx²/mg

Where h is the height of the slope, m is the mass of ice cube, k is the spring constant and x is the compressed length o the spring and g is gravitational acceleration.

h = 1/2*kx²/mg

h = 1/2*30(0.1)²/0.063*9.8

h = 0.242 m

From trigonometry ratio,

sinθ = h/d

d = h/sinθ

d = 0.242/sin(30)

d = 0.48 m

Therefore, when the ice cube is released, it will travel a total distance 0.48 up the slope before reversing direction.

3 0
3 years ago
C) An identical spring is pulled with a force or 75 N The elastie limit of the spring is 72N
tiny-mole [99]

Answer:

Spring cannot return to its original, since a part of its deformation is <u>plastic</u>, not <u>elastic</u>.

Explanation:

Physically speaking, stress is equal to the axial force divided by effective transversal area of spring. In addition, springs have usually a linear relationship between stress and strain in <u>elastic region</u>, since they are made of ductile materials. Axial force is directly proportional to axial stress, which is also directly proportional to axial strain.

Then, if force is greater than force associated with elastic limit of the spring, then spring cannot return to its original, since a part of its deformation is <u>plastic</u>, not <u>elastic</u>.

8 0
3 years ago
Fill in the chart with the correct values of F for each change in the system described in questions
Katarina [22]

Answer:

We know that the gravitational force F between two masses P and Q, that are separated by a distance R is:

F = G*\frac{P*Q}{R^2}

Where G is the gravitational constant.

a) Mass P is doubled, then we have 2*P instead of P, the new force is:

F' = G*\frac{(2*P)*Q}{R^2}  = 2*(G*\frac{P*Q}{R^2} ) = 2*F

b) Now R is doubled, then instead of R, we have 2*R:

F' = G*\frac{P*Q}{(2*R)^2}  = G*\frac{P*Q}{4*R^2}  = G*\frac{P*Q}{R^2}*(1/4) = F/4

c) Now we replace P by 2*P, and Q by 3*Q

F' = G*\frac{(2*P)*(3*Q)}{R^2}  = 2*3*(G*\frac{P*Q}{R^2} ) = 6*F

d) The entire mass of the system is increased by a factor of 4, then both of the individual masses are increased by a factor of 4.

Then we need to replace P by 4*P, and Q by 4*Q.

F' = G*\frac{(4*P)*(4*Q)}{R^2}  = 4*4(G*\frac{P*Q}{R^2} ) = 16*F

e) Now we replace R by R/2.

F' = G*\frac{P*Q}{(R/2)^2}  = G*\frac{P*Q}{R^2/4}= 4*G\frac{P*Q}{R^2} = 4*F

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3 years ago
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