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lawyer [7]
3 years ago
10

Please answer the following ASAP

Mathematics
1 answer:
mr Goodwill [35]3 years ago
8 0

Answer:

Graphing:  Graphing is the best method to use when introducing a new student to solving systems of two equations in two variables, because it gives them a visiual to recognize what they are looking for.  Graphing is less exact and often takes more time than the other methods.  I only recommend graphing to find a solution if the problem comes with a graph already drawn and the intersection appears to be on an exact coordinate.

Substitution:  Substition gives that advantage of having an equation alrady written for the second variable when you find the first one.  Substitution is best used when one (or both) of the equations is already solved for one of the variables.  It also works well if one of the variables has a coefficient of 1.

Elimination:  Elimination is the method that I use almost every time.  If you are not sure which method to use, I recommend that you use elimination.  Elimination is best used when both equations are in standard form (Ax + By = C).  Elimination is also the best method to use if all of the variables have a coefficient other than 1.

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Someone please answer !!!!
Goryan [66]
The answer is C

By the way, that expression means "n choose k". Hope I helped!
7 0
3 years ago
Read 2 more answers
Substitution property of equality if y=-5 and 7x+y=11, then____. A. 7(-5) + y=11 B.7x-5=11 C.7x+5=11 D.-5+y=11
jolli1 [7]
7x+y=11 where y= -5                                                                                              So, when we substitute y in the equation then,
7x + (-5) = 11 that is 7x - 5 = 11....
So, B. is the right answer.

3 0
3 years ago
What is this number in standard form? <br> (8×100)+(4×1)+(6×1100)+(3×11,000)
Korvikt [17]

Answer:

40404

Step-by-step explanation:

is this helpful????

5 0
3 years ago
Read 2 more answers
Você precisa colocar suas renas, Raposa, Trovão, Cometa e Relâmpago, em uma fila única para puxar o seu trenó. No entanto, Comet
Gennadij [26K]

Answer:

If the reindeer do not fight, there are 5!=120 ways to line them up in a straight line.

Out of these, Bloopin and Rudy are together in 4!=24 times.  Similarly Rudy and Bloopin will be together 4!=24 times.  So the number of ways they are not together is 120-24-24=72 ways.

Hope this helps.    :)

Step-by-step explanation:

Spanish:

Si los renos no luchan, hay 5! = 120 formas de alinearlos en línea recta.

De estos, Bloopin y Rudy están juntos en 4! = 24 veces. De manera similar, Rudy y Bloopin estarán juntos 4! = 24 veces. Entonces, el número de formas en que no están juntas es 120-24-24 = 72 formas.

Espero que esto ayude       :)

4 0
3 years ago
The area of a square is 81 centimeters find the length of the length find the diagonal
EleoNora [17]

Length = √area  = √81 = 9

diagonal = √2 * side = √2*9 = 9√2

5 0
4 years ago
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