Answer:
The answer to the question are
(B) The set is not a vector space because it is not closed under addition. and
(D) The set is not a vector space because an additive inverse does not exist.
Step-by-step explanation:
To be able to identify the possible things that can affect a possible vector space one would have to practice on several exercises.
The vector space axioms that failed are as follows
(B) The set is not a vector space because it is not closed under addition.
(2·x⁸ + 3·x) + (-2·x⁸ +x) = 4·x which is not an eighth degree polynomial
(D) The set is not a vector space because an additive inverse does not exist.
There is no eight degree polynomial = 0
The axioms for real vector space are
- Addition: Possibility of forming the sum x+y which is in X from elements x and y which are also in X
- Inverse: Possibility of forming an inverse -x which is in X from an element x which is in X
- Scalar multiplication: The possibility of forming multiplication between an element x in X and a real number c of which the product cx is also an element of X
1313 cups yogurt multiplied by 7 = 9191 cups of yogurt
Check the picture below.
the distance from 1,2 to 1,8 is simply 6 units, we can read that off the grid. Now let's see what the other distances are, and add them all up to get the perimeter.
![\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{2})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AC=\sqrt{(5-1)^2+(5-2)^2}\implies AC=\sqrt{4^2+3^2} \\\\\\ AC=\sqrt{25}\implies AC=5 \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20A%28%5Cstackrel%7Bx_1%7D%7B1%7D~%2C~%5Cstackrel%7By_1%7D%7B2%7D%29%5Cqquad%20C%28%5Cstackrel%7Bx_2%7D%7B5%7D~%2C~%5Cstackrel%7By_2%7D%7B5%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20AC%3D%5Csqrt%7B%285-1%29%5E2%2B%285-2%29%5E2%7D%5Cimplies%20AC%3D%5Csqrt%7B4%5E2%2B3%5E2%7D%20%5C%5C%5C%5C%5C%5C%20AC%3D%5Csqrt%7B25%7D%5Cimplies%20AC%3D5%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf B(\stackrel{x_1}{1}~,~\stackrel{y_1}{8})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) \\\\\\ BC=\sqrt{(5-1)^2+(5-8)^2}\implies BC=\sqrt{4^2+3^2} \\\\\\ BC=\sqrt{25}\implies BC=5 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{perimeter}{6+5+5\implies 16}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20B%28%5Cstackrel%7Bx_1%7D%7B1%7D~%2C~%5Cstackrel%7By_1%7D%7B8%7D%29%5Cqquad%20C%28%5Cstackrel%7Bx_2%7D%7B5%7D~%2C~%5Cstackrel%7By_2%7D%7B5%7D%29%20%5C%5C%5C%5C%5C%5C%20BC%3D%5Csqrt%7B%285-1%29%5E2%2B%285-8%29%5E2%7D%5Cimplies%20BC%3D%5Csqrt%7B4%5E2%2B3%5E2%7D%20%5C%5C%5C%5C%5C%5C%20BC%3D%5Csqrt%7B25%7D%5Cimplies%20BC%3D5%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20%5Cstackrel%7Bperimeter%7D%7B6%2B5%2B5%5Cimplies%2016%7D~%5Chfill)
Answer:
16/81
Step-by-step explanation:
according to BODMAS-first settle the bracket
8×2=16
3^4=81
therefore it becomes
16/81.
Answer:
A conjunction is a compound statement formed by combining two statements using the word and . In symbolic logic, the conjunction of p and q is written p∧q . A conjunction is true only if both the statements in it are true.
Step-by-step explanation:
