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Kay [80]
3 years ago
12

What is molecular gastronomy

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0

Answer:

Molecular gastronomy, or progressive cuisine, is a movement that incorporates science and new techniques in the preparation, transformation and artistic presentation of food. It is the study of molecules as they relate to the chemical and physical processes of cooking.

Step-by-step explanation:

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Given the graph of a line y=−x. Write an equation of a line which is perpendicular and goes through the point (8,2).
coldgirl [10]

Answer:

y = x - 6

Step-by-step explanation:

The slope of y = -x is -1, so the slope of any line perpendicular to y = -x is +1.  Thus,

y = mx + b becomes 2 = 1(8) + b, so that b = -6.

The desired equation is y = x - 6.

Check:  Does (8,2) lie on this line?  Is 2 = 8 - 6 true?  YES.


6 0
3 years ago
Read 2 more answers
I need help asap someone please help me i dont understand this question so can someone help me
eduard

Answer:

we conclude that:

\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}

Step-by-step explanation:

Given the expression

\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}

=\frac{2p}{4p^2-1}\times \frac{6p+3}{6p^3}

=\frac{2p}{4p^2-1}\times \frac{2p+1}{2p^3}

\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}

=\frac{2p\left(2p+1\right)}{\left(4p^2-1\right)\times \:2p^3}

cancel the common factor: 2

=\frac{p\left(2p+1\right)}{\left(4p^2-1\right)p^3}

cancel the common factor: p

=\frac{2p+1}{p^2\left(4p^2-1\right)}

=\frac{2p+1}{p^2\left(2p+1\right)\left(2p-1\right)}

cancel the common factor: 2p+1

=\frac{1}{p^2\left(2p-1\right)}

Expanding

=\frac{1}{2p^3-p^2}

Thus, we conclude that:

\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}

7 0
3 years ago
The Foley Products Company has designed a new blend of concrete they believe will be twice as strong as their current high quali
Hitman42 [59]

Answer:

All of the batches of the new blend of concrete made at their plant in a particular week.

Step-by-step explanation:

The population refers to all the subjects or data which which meets the condition or requirement of a certain experiment or research. This means that all the set of similar items or subjects which is of interest in a certain study is the population. In the scenario above, the population will be the set of all the new blend concrete which are made in the plant within a certain week. Thereafter, if a sample is required it will be drawn from these set of data or observation.

8 0
2 years ago
Q5. A bumper bag of icing sugar weighs 23.4 kg
VARVARA [1.3K]
Q5. 23
Q6. 2.4
Q7. 4.7
Q8. $19.20
Q9. 4.77
6 0
3 years ago
For each level of precision, find the required sample size to estimate the mean starting salary for a new CPA with 95 percent co
Rzqust [24]

Answer:

(a) Margin of error ( E) = $2,000 , n = 54

(b)   Margin of error ( E) = $1,000 , n = 216

(c)   Margin of error ( E) = $500 , n= 864

Step-by-step explanation:

Given -

Standard deviation \sigma = $7,500

\alpha = 1 - confidence interval = 1 - .95 = .05

Z_{\frac{\alpha}{2}} =  Z_{\frac{.05}{2}} = 1.96

let sample size is n

(a) Margin of error ( E) = $2,000

Margin of error ( E)  = Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}

                           E   = Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}

Squaring both side

E^{2} = 1.96^{2}\times\frac{7500^{2}}{n}

n =\frac{1.96^{2}}{2000^{2}} \times 7500^{2}

n =  54.0225

n = 54 ( approximately)

(b)   Margin of error ( E) = $1,000

          E     = Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}

         1000   =  Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}

Squaring both side

1000^{2} = 1.96^{2}\times\frac{7500^{2}}{n}

n =\frac{1.96^{2}}{1000^{2}} \times 7500^{2}

n = 216

(c)   Margin of error ( E) = $500

   E = Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}

  500 = Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}

Squaring both side

500^{2} = 1.96^{2}\times\frac{7500^{2}}{n}

n =\frac{1.96^{2}}{500^{2}} \times 7500^{2}

n = 864

7 0
3 years ago
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