Answer: B
Step-by-step explanation:
2.49 and 2.51 :)
I hope it helped :)
Answer:
Truck can safely carry <em>2310 pounds </em> of cargo.
Step-by-step explanation:
Given the safety limit of weight to cross the bridge safely is 4 tons.
1 ton is equal to 2000 pounds.
so, 4 tons are equal to 2000
4 = 8000 pounds
Now, given that
weight of empty truck and driver = 5690 pounds
To find:
Weight of cargo that the truck can safely carry ?
Solution:
Total weight of the truck is actually the combined weight of the empty truck, the drive and the cargo carried in it.
So, Total Weight allowed = 8000 pounds = 5690 pounds + Weight of Cargo
Weight of Cargo = 8000 - 5690 pounds
Weight of Cargo = <em>2310 pounds</em>
Truck can safely carry <em>2310 pounds </em> of cargo.
Answer:
Since the slope of the line x= - 5 is infinite
The line will be parallel to y axis.
And the line passes through - 2, so the equation will become x= -2
Answer:
a

b

Step-by-step explanation:
Let the random X variable representing the 6 companies that give 4 weeks of vacation after 15 years of employment:
-let p=0.5 be the probability of vacation. Since the companies are independent, X assumes a binomial random variable:
#Probability that the number of companies that give vacation is anywhere from 2 to 5:
We use equation 1;

Hence the probability that between 2 and 5 companies give vacation is 0.875
b. The probability that fewer than 3 companies give vacation is calculated as:
From equation one we get:

Hence the probability that less than three companies give vacation is 0.3432