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stiks02 [169]
3 years ago
11

1. Greg buys(21 bags of nails. Each bag has85 nails in it. Greg

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
8 0

Answer:

dndiduned

Step-by-step explanation:

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What is u = kx + ух, for x
Ivahew [28]

Answer:

<h2>x=  \frac{u}{k + y}</h2>

Step-by-step explanation:

u = kx + ух

First of all factorize x out at the right side of the equation

That's

u = x(k + y)

Divide both sides by ( k + y) to make x stand alone

That's

<h3>\frac{x(k + y)}{k + y}  =  \frac{u}{k + y}</h3>

We have the final answer as

<h3>x =  \frac{u}{k + y}</h3>

Hope this helps you

6 0
4 years ago
URGENT ANSWER NOW In △ABC, A=59∘, a=20, and c=21. What are the two possible values for angle C to the nearest tenth of a degree?
PilotLPTM [1.2K]

Answer:

The two possible values of C are 64.2° and 115.8°

Step-by-step explanation:

* In ΔABC

- a, b, c are the lengths of its 3 sides, where

# a is opposite to angle A

# b is opposite to angle B

# c is opposite to angle C

- m∠A = 59°

- a = 20

- c = 21

* To find the distance m∠C we can use the sin Rule

- In any triangle the ratio between the length of each side

 to the measure of each opposite angle are equal

- c/sinC = a/sinA = b/sinB

* Lets use it to find the m∠C

∵ 21/sinC = 20/sin(59)

∴ sin(C) = 21 × sin(59) ÷ 20 = 0.9000256657

∴ m∠C = sin^-1(0.9000256657)  = 64.16144°

∴ m∠C = 64.2°

∵ The value of sin(C) is positive

∴ Angle C may be in the first quadrant (acute angle)

  or in the second quadrant (obtuse angle)

∴ The other measure of ∠C = 180 - 64.2 = 115.8

* The two possible values of C are 64.2° and 115.8°

6 0
3 years ago
True or False: This table describes a linear function. <br> XY<br> 1 5<br> 2 8<br> 3 10
VLD [36.1K]

Answer:

False

Step-by-step explanation:

The slope is not constant

5 0
2 years ago
10 points please help and explain how ;) brainliest answer first person to get it right
OverLord2011 [107]

Answer:

Open dot at -1 and shaded to the right.

Step-by-step explanation:

First you have to solve the inequality are you get |y|>-1

Now you can plot the inequality by placing an open dot on -1 since the inequality is greater than.

Since the inequality is greater than, you also have to shade when all y values are greater than -1 so you would shade to the right.

5 0
3 years ago
I'm lost.. How do you even start it???
Anastasy [175]
2x+y=4\\&#10;-x+y=1\\\\&#10;2x+y=4\\&#10;\underline{x-y=-1}\\&#10;3x=3\\&#10;x=1\\\\&#10;1-y=-1\\&#10;y=2&#10;
7 0
4 years ago
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