All categories

3 years ago

Twenty-four is what % of 80.

Mathematics

1 answer:

sergeinik [125]3 years ago

6 0

80/24 = 10/3

(10/3) * 10 = 33.333%

Hope this helps ! :)

You might be interested in

Hii! I need some help, would anyone mind helping me?

Kisachek [45]

Step-by-step explanation:

${x}^{2} - 14x - 25 {y}^{2} + 100y = 76$

Factor by grouping,

$( {x}^{2} - 14x) - (25 {y}^{2} - 100y) = 76$

Complete the square, with the x variables,

$( {x}^{2} - 14x + 49) - (25 {y}^{2} - 100y) = 125$

Factor out 25 for the y variables

$( {x}^{2} - 14x + 49) - 25( {y}^{2} - 4y) = 125$

Complete the square

$( {x}^{2} - 14x + 49) - 25( {y}^{2} - 4y + 4) = 25$

Simplify the perfect square trinomial

$(x - 7) {}^{2} - 25(y - 2) {}^{2} = 25$

Make the right side be 1 so divide everything by 25.

$\frac{(x - 7) {}^{2} }{25} - (y - 2) {}^{2} = 1$

Here our center is (7,2).

8 0

2 years ago

(4, -3), (x, 1); slope -4

Alexandra [31]

Answer:

x = 3

Step-by-step explanation:

$m = \frac{y \frac{}{2} - y \frac{}{1} }{x \frac{}{2} - x \frac{}{1} }$

m = slope

x, y = coordinates

$- 4 = \frac{1 - ( - 3)}{x - 4} \\ - 4(x - 4) = 1 + 3 \\ - 4x + 16 = 4 \\ - 4 x = 4 - 16 \\ - 4x = - 12 \\ x= \frac{ - 12}{ - 4} \\ x = 3$

3 0

3 years ago

What is the radius of a circle whose equation is x2 + (y – 8)2 = 25?

Dafna11 [192]

Use photo math :) and you will get your answer

8 0

4 years ago

Read 2 more answers

Help I don’t get these at all

uysha [10]

Answer: its D. 24

Step-by-step explanation:

5 0

3 years ago

When a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a ra

Sergeu [11.5K]

Answer:

$r=\sqrt{10}\text{ m}$

Step-by-step explanation:

We have been given that when a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. We are asked to find the approximate radius of tank in meters.

We will use volume of cylinder formula to solve our given problem as:

$V=\pi r^2h$ , where,

r = Radius,

h = Height of cylinder.

Since the level of water in the tank rises at a rate of 0.7 meters per hour, so height of cylinder would be $h = 0.7$ meters at $V=22\text{ m}^3$ .

Upon substituting these values in above formula, we will get:

$22\text{ m}^3=\frac{22}{7}\cdot r^2(0.7\text{ m})$

$22\text{ m}^3=\frac{22}{10}\cdot r^2\text{ m}$

$\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}=r^2$

$r^2=\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}$

$r^2=10\text{ m}^2$

Now, we will take positive square root of both sides as radius cannot be negative.

$\sqrt{r^2}=\sqrt{10\text{ m}^2}$

$r=\sqrt{10}\text{ m}$

Therefore, radius of tank would be approximately square root of 10 m.

5 0

3 years ago