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ivolga24 [154]
3 years ago
10

Halp plz will give 50 points )):$&/&/!:&:9’sbs

Mathematics
1 answer:
Phoenix [80]3 years ago
4 0

Answer:

lol i did this iready too! the answer is 124

Step-by-step explanation:

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Please help this is due in 10 minutes!
Reptile [31]

Answer:

The answer is 16÷1/10

Step-by-step explanation:

That equals 160ft

7 0
3 years ago
According to the​ research, 43​% of homes sold in a certain month and year were purchased by​ first-time buyers. A random sample
vovangra [49]

Answer Do it

Step-by-step explanation 165 divided by 100 =x times 43

4 0
4 years ago
1) Find Area of this polygon 4 cm I 5cm 1 cm 7 cm and the other one<br>​
jasenka [17]
For the top problem, you split it to make two rectangles and so you have 4 times 5 =20 plus 1 times 3 so the answer is 23cm squared
7 0
3 years ago
Arrange the following polynomial into descending order for x, then interpret the degree of the 3rd term. 2xy4 + 2x2y − 3y2 + 10x
malfutka [58]
To arrange the given polynomial in descending order of x, we only look at the exponent of x in each term and then write it in decreasing order of the value. We do as follows:

2xy^4 + 2x^2y − 3y^2 + 10x^3<span>
10x^3 + 2x^2 + 2xy^4 - 3y^2

The degree of the third term would be 5. The degree of a term is the sum of the exponents of the variables involved in the term.  
</span>
6 0
3 years ago
find the surface area of a right regular hexagonal pyramid with sides 3 cm and slant heights 6cm. show all of your work.​
DedPeter [7]

Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

Step-by-step explanation:

Given as , for regular hexagonal pyramid :

The of base side = 3 cm

The slant heights = 6 cm

Now ,

The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}

Or, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}

Or,  The surface area of right regular hexagonal pyramid = 23.38 + 9 × \frac{171}{4}

∴  The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538

I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842

So,  The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer

6 0
4 years ago
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