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leva [86]
3 years ago
5

Define a JavaScript function named showGrades which does not have any parameters. Your function should create and return an arra

y containing 3 Numbers. The values for each of these entries should be: get the value from the div whose id is "GradeA" and store it at index 0 of your array; get the value from the div whose id is "Passing" and store it at index 1 of your array; and get the value from the div whose id is "Learning" and store it at index 2 of your array. Your must then encode the array as a JSON blob and return that JSON blob.
Computers and Technology
1 answer:
grandymaker [24]3 years ago
8 0

Answer:

see explaination

Explanation:

//selective dev elements by id name

var gradeA = document.querySelector("#GradeA");

var passing = document.querySelector("#Passing");

var learning = document.querySelector("#Learning");

//function showGrades

function showGrades() {

var arr = [];

//converting string to int and inserting into array

arr[0] = parseInt(gradeA.textContent);

arr[1] = parseInt(passing.textContent);

arr[2] = parseInt(learning.textContent);

//creating json blob

var blob = new Blob(new Array(arr), {type:"text/json"});

return blob;

}

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Implementations <br> in c++ programming when finding lcm and gcd in c++​
vazorg [7]

Answer:

#include<iostream>

using namespace std;

int lcm(int m, int n) {

  int a;

  a = (m > n) ? m: n;

  while (true) {

     if (a % m == 0 && a % n == 0)

        return a;

        ++a;

  }

}

int gcd(int m, int n) {

  int r = 0, a, b;

  a = (m > n) ? m : n;

  b = (m < n) ? m : n;

  r = b;

  while (a % b != 0) {

     r = a % b;

     a = b;

     b = r;

  }

  return r;

}

int main(int argc, char **argv) {

  cout << "Enter the two numbers: ";

  int m, n;

  cin >> m >> n;

  cout << "The LCM of two numbers is: " << lcm(m, n) << endl;

  cout << "The GCD of two numbers is: " << gcd(m, n) << endl;  

  return 0;

}

Explanation:

7 0
3 years ago
Have you searched Buzz Ch.at on playstore​
deff fn [24]

Answer:

Reorder terms.

y=52x−1

Cancel the common factor of 22.Factor 22 out of −2-2.

y−4=5x2+52⋅(2(−1))y-4=5x2+52⋅(2(-1))

Cancel the common factor.

y−4=5x2+52⋅(2⋅−1)y-4=5x2+52⋅(2⋅-1)

Rewrite the expression.

y−4=5x2+5⋅−1y-4=5x2+5⋅-1

Multiply 55 by −1-1.

y−4=5x2−5

3 0
3 years ago
Alice's Restaurant Supply offers a line of specialty food products to institutional
Illusion [34]

Answer:

1) the wireless standards that can be implemented are; IEEE 802.11a, IEEE 802.11b, IEEE 802.11g and IEEE 802.11n. The pros and cons are in the attachment

2) 802.11g can be implemented in alice's restaurant. This is because it provides the fastest speed and has a wide range which will not be easily disturbed by other devices

3) Please check the attachment

4) Please check the attachment.

Explanation:

3 0
3 years ago
Which of the following is another term for a subfolder?
LenKa [72]
Subdirectory

Have a great day! c:
5 0
3 years ago
CHALLENGE ACTIVITY |
fredd [130]

Answer:

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

The maxSum is a double type variable which is assigned the maximum of the two variables numA numB PLUS the maximum of the two variables numY numZ using FindMax function. The FindMax() method is called twice in this statement one time to find the maximum of numA and numB and one time to find the maximum of numY numZ. When the FindMax() method is called by passing numA and numB as parameters to this method, then method finds if the value of numA is greater than that of numB or vice versa. When the FindMax() method is called by passing numY and numZ as parameters to this method, then method finds if the value of numY is greater than that of numZ or vice versa. The PLUS sign between the two method calls means that the resultant values returned by the FindMax() for both the calls are added and the result of addition is assigned to maxSum.

Explanation:

This is where the statement will fit in the program.

#include <iostream>

using namespace std;

double FindMax(double num1, double num2) {

  double maxVal = 0.0;    

  if (num1 > num2) { // if num1 is greater than num2,

     maxVal = num1;  // then num1 is the maxVal.    }

  else {          

     maxVal = num2;  // num2 is the maxVal.   }

  return maxVal; }  

int main() {

  double numA;

  double numB;

  double numY;

  double numZ;

  double maxSum = 0.0;  

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

  cout << "maxSum is: " << maxSum << endl;   }

Lets take an example to explain this. Lets assign values to the variables.

numA = 6.0

numB = 3.0

numY = 4.0

numZ = 9.0

maxSum =0.0

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

FindMax(numA,numB) method call checks if numA>numB or numB>numA and returns the maximum of the two. Here numA>numB because 6.0 is greater than 3.0. So the method returns numA i.e. 6.0

FindMax(numY, numZ) method call checks if numY>numZ or numZ>numY and returns the maximum of the two. Here numZ>numY because 9.0 is greater than 4.0. So the method returns numZ i.e. 9.0

FindMax(numA, numB) + FindMax(numY, numZ) this adds the two values returned by the method FindMax for each call.

FindMax returned maxVal from numA and numB values which is numA i.e. 6.0.

FindMax returned maxVal from numY and numZ values which is numZ i.e. 9.0.

Adding these two values 9.0 + 6.0 = 15

So the complete statement  FindMax(numA, numB) + FindMax(numY, numZ) gives 15.0  as a result.

This result is assigned to maxSum. Hence

maxSum = 15

To see the output on the screen you can use the print statement as:

cout<<maxSum;

This will display 15

6 0
3 years ago
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