-8(2z - 7c) use z = 5 and c = 2

2 answers:

6 0

Answer is 32

Step 1. Solve inside the parentheses so 2x5= 10 and 7x2=14 then you have -8(10-14)

Step 2. Distribute -8 so -8x10= -80 and -8x14= -112 = -80- -112

Step 3. Subtract totals: -80- -112 = 32 it’s a positive because of the two negatives being subtracted together

Sergio039 [100]3 years ago

4 0

Answer:

The answer is

-8(2×5-7×2)

=-8(10-14).

= -8(-4)

= 32.

You might be interested in

On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole. On his second stroke, the ball traveled 79 met

Sav [38]

Answer:

0.395 kilometre

Step-by-step explanation:

Given:

On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole.

On his second stroke, the ball traveled 79 meters and went into the hole.

<u>Question asked:</u>

How many kilometres from the hole was Martin when he started?

<u>Solution:</u>

Let distance from Martin starting point to the hole in meters = $x$

On Martin's first stroke, ball traveled = $\frac{4}{5} \ of \ total \ distance\ to\ the\ hole$

$=\frac{4}{5} \times x=\frac{4x}{5}$

On his second stroke, the ball traveled and went to the hole = 79 meters

Total distance from starting point to the hole = Ball traveled from first stroke + Ball traveled from second stroke

$x=\frac{4x}{5} +79\\ \\ Subtracting\ both\ sides\ by \ \frac{4x}{5}\\ \\ x- \frac{4x}{5}= \frac{4x}{5}- \frac{4x}{5}+79\\ \\ \frac{5x-4x}{5} =79\\ \\ By \ cross\ multiplication\\ \\ x=79\times5\\ \\ x=395\ meters$