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3 years ago

Which description matches the transformations y=cosx undergoes to produce y=3cos(-2x)

Mathematics

2 answers:

kap26 [50]3 years ago

7 0

Answer:

d) horizontal stretch by factor 2, reflection across the x-axis, then vertical stretch by factor 3.

Step-by-step explanation:

a p e x :)

Hoochie [10]3 years ago

4 0

Let us check the transformations. The first step is regarding the argument of the function, the -2x part. So, first of all, the minus sign implies that the function is reflected along the y-axis since f(x) is replaced with f(-x). However, cosx is symmetric along that axis so there is no change on the graph. Also, the 2 factor means that the function is compressed along the x-axis, since now f(2) corresponds to f(1) etc. (if we substitute 1 in the cos(2x), it is as if substituting 2 in the origninal function cosx). Finally, we have that the factor 3 in front of cos, implies that the function is dilated along the y-axis; the highs become 3 times higher and the lows 3 times low.

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Graph the linear equation find three points that solve the equation, then plot on the graph y=-x+2

Maslowich

Step-by-step explanation: x= 2-y then plug that in for x so y= 2-y+2;

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3 years ago

Antuan deposited $2590 into a 3 year CD at an interest rate of 2.3% compounded quarterly.

lora16 [44]

Answer:

the interest rate is $183.89 =~ $ 184

Step-by-step explanation:

In this question, Antuan deposited $2590 into a 3 year CD (Certificate of Deposit) at an interest rate of 2.3% compounded quarterly. We need to find the interest account earned after 3 years.

Formula used will be :

$Interest = P ( 1 + r/n) ^ n ^ t - P$

Where

P= Principal amount

r= interest rate (in decimals)

n= no of times the interest is compounded

t = no of years

Here we are subtracting P because we only need interest amount and not the future value.

Using this formula and finding the value will be:

P= $2590

r = 2.3 % or 0.023

n = 4

t = 3

$Interest = 2590 * ( 1 - 0.023 / 4) ^ 4^ * ^ 3 - 2590$

$Interest= 2590 (1.071) -2590\\Interest= 2773.89 - 2590\\Interest= 183.89$

So the interest rate is $183.89 =~ $ 184

7 0

3 years ago

Given logbM=3.2 logbN=-1.5 and logbP=2.4 find the value of logb(m^2N/p)

artcher [175]

The formulas:
$\log_a (xy)=\log_a x + \log_a y \\
\log_a (\frac{x}{y})=\log_a x - \log_a y \\
\log_a (x^n)n \log_a x$

Expand the expression:
$\log_b (\frac{m^2n}{p})=\log_b m^2 + \log_b n - \log_b p= 2 \log_b m+\log_b n - \log_b p$

Plug the values into the expression:
$\log_b m=3.2 \\ \log_b n=-1.5 \\ \log_b p=2.4 \\ \\
2 \log_b m+\log_b n - \log_b p=2 \times 3.2-1.5-2.4=6.4-3.9=2.5 \\ \\
\boxed{\log_b (\frac{m^2n}{p})=2.5}$

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3 years ago

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Naddika [18.5K]

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2 years ago

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noname [10]

Answer:

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